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Q.A football of mass 0.45 kg is at rest on the ground. A player's boot applies a force of 90 N to it.

(i) Using F = ma, calculate the acceleration of the ball.
(ii) If the boot stays in contact with the ball for 0.02 s, calculate the speed with which the ball leaves the foot.
(iii) State which of Newton's laws you have used and what the result tells the coach about kicking harder.
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This problem applies Newton's Second Law of Motion to calculate the acceleration of a football when kicked and its final speed, demonstrating how force and contact time influence the ball's velocity.

Understanding how forces affect motion is fundamental in Physical Education, especially in sports like football. The key concept here is Newton's Second Law of Motion, which describes the relationship between an object's mass, the force applied to it, and the resulting acceleration.

Newton's Second Law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that if you apply a larger force to an object, it will accelerate more rapidly, and if an object has more mass, it will accelerate less for the same amount of force. In the context of kicking a football, the player's boot applies a force to the ball, causing it to accelerate from rest to a certain speed. The magnitude of this acceleration, and consequently the final speed of the ball, depends on how hard the player kicks (the force applied) and the mass of the ball.

(i) Using F = ma, calculate the acceleration of the ball.

To calculate the acceleration, we use Newton's Second Law of Motion.

The given values are:

  • Mass of the football (m) = 0.45 kg
  • Force applied by the boot (F) = 90 N

F = ma

Where:

  • F is the net force acting on the object (in Newtons, N)
  • m is the mass of the object (in kilograms, kg)
  • a is the acceleration of the object (in meters per second squared, m/s²)

We need to find a, so we rearrange the formula to a = F/m.

  1. Substitute the given values into the formula: a = (90 N)/(0.45 kg)
  2. Perform the calculation: a = 200 m/s²

The acceleration of the ball is 200 m/s².

(ii) If the boot stays in contact with the ball for 0.02 s, calculate the speed with which the ball leaves the foot.

To calculate the final speed, we use a kinematic equation that relates initial velocity, acceleration, time, and final velocity.

The known values are:

  • Initial velocity (u) = 0 m/s (since the ball is at rest)
  • Acceleration (a) = 200 m/s² (calculated in part i)
  • Time of contact (t) = 0.02 s

v = u + at

Where:

  • v is the final velocity (in meters per second, m/s)
  • u is the initial velocity (in meters per second, m/s)
  • a is the acceleration (in meters per second squared, m/s²)
  • t is the time (in seconds, s)
  1. Substitute the known values into the formula: v = 0 m/s + (200 m/s²)(0.02 s)
  2. Perform the calculation: v = 0 + 4 m/s v = 4 m/s

The speed with which the ball leaves the foot is 4 m/s.

(iii) State which of Newton's laws you have used and what the result tells the coach about kicking harder.

The law used in part (i) to calculate the acceleration of the ball is Newton's Second Law of Motion.

The results from these calculations tell a coach important information about how to kick harder, meaning how to achieve a higher final speed for the ball: …

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