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Q.Show that the relation RR defined in the set AA of all triangles as R={(T1,T2) ; T1 is similar to T2}R = \{(T_1, T_2)\ ;\ T_1 \text{ is similar to } T_2\}, is an equivalence relation. OR Write the following function in simplest form:
[!FORMULA] tan⁡−1(3a2x−x3a3−3ax2), a>0; −a3<x<a3\tan^{-1}\left(\dfrac{3a^2x - x^3}{a^3 - 3ax^2}\right),\ a>0;\ -\dfrac{a}{\sqrt{3}} < x < \dfrac{a}{\sqrt{3}}

Haryana BsehBSEH Intermediate Board 2024Subjective· 3mImportance★★★★★
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RR is reflexive, symmetric and transitive, hence an equivalence relation.

R={(T1,T2):T1 is similar to T2}R=\{(T_1,T_2): T_1 \text{ is similar to } T_2\} on the set of all triangles.

Reflexive: every triangle TT is similar to itself (identical shape, ratio 1:11:1), so (T,T)∈R(T,T)\in R for every triangle TT. Hence RR is reflexive.

Symmetric: if T1T_1 is similar to T2T_2 (their corresponding angles are equal and sides proportional), then T2T_2 is similar to T1T_1 by the same correspondence, in reverse. So (T1,T2)∈R  ⟹  (T2,T1)∈R(T_1,T_2)\in R \implies (T_2,T_1)\in R. Hence RR is symmetric.

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