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Q.How much current flows through a 2 kΩ resistor when a potential difference of 4 V is applied across its ends?

Haryana BsehBSEH Intermediate Board 2019Subjective· 1mImportance★★★★★
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By Ohm's law, I=V/R=4 V/2000 Ω=2 mAI = V/R = 4\text{ V}/2000\,\Omega = 2\text{ mA}.

Given V=4 VV = 4\ \text{V}, R=2 kΩ=2000 ΩR = 2\ \text{k}\Omega = 2000\ \Omega.

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