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Q.Explain the principle of a moving coil galvanometer. How can it be converted into an ammeter? OR Derive an expression for the force between two parallel straight conductors carrying currents in the same direction. Hence define one ampere.

Haryana BsehBSEH Intermediate Board 2018Subjective· 5mImportance★★★★★
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A moving-coil galvanometer deflects in proportion to the current through its coil (due to the torque on it in a magnetic field); shunting it with a small parallel resistance converts it into an ammeter of the desired range.

Principle of a moving coil galvanometer: A rectangular coil of many turns, wound on a light aluminium frame, is suspended (or pivoted) between the poles of a strong permanent magnet, with the magnetic field made radial by using cylindrical pole pieces and a soft-iron core — this ensures the plane of the coil always stays parallel to B⃗\vec{B}, so the deflecting torque does not vary with the coil's orientation.

When a current II flows through the coil (of area AA, NN turns) placed in field BB, each turn experiences a torque, and the net deflecting torque is

τdef=NIAB\tau_{def} = NIAB

This is balanced, at equilibrium deflection θ\theta, by the restoring torque of a spring (torsion constant kk): τres=kθ\tau_{res} = k\theta. Equating,

NIAB=kθ  ⟹  θ=(NABk)INIAB = k\theta \implies \theta = \left(\dfrac{NAB}{k}\right)I

Since NN, AA, BB, kk are constants for a given galvanometer, θ∝I\theta \propto I — the deflection is directly proportional to the current, which is what allows the instrument to measure current (or, via a scale, voltage).

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