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Q.Write the principle of a moving coil galvanometer. How is it converted into an ammeter ? Write the expression for its current sensitivity. OR Write the principle of a moving coil galvanometer. How is it converted into a voltmeter ? Write the expression for its voltage sensitivity.

Haryana BsehBSEH Intermediate Board 2024Subjective· 5mImportance★★★★★
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The galvanometer works on the torque a magnetic field exerts on a current loop; a small shunt resistance in parallel turns it into an ammeter that measures large currents without disturbing the circuit.

Principle of a moving coil galvanometer: When a current-carrying rectangular coil is placed in a uniform radial magnetic field, the coil experiences a torque that tends to rotate it. This deflecting torque is:

τ = NIAB

where N = number of turns, I = current, A = area of the coil, B = magnetic field strength. This magnetic torque is balanced by a restoring torque from a spring (τrestoring = kφ, k = torsional constant, φ = deflection angle), so at equilibrium:

NIAB = kφ ⟹ φ = (NAB/k) I

Since φ ∝ I, the deflection can be used to measure current.

Conversion to an ammeter: A galvanometer has a small resistance G and can safely carry only a small current Ig (full-scale deflection current). To measure a much larger current I, a small resistance called a SHUNT (S) is connected in PARALLEL with the galvanometer. Most of the current bypasses the galvanometer through the low-resistance shunt, while only Ig flows through the galvanometer coil. Using the parallel-current-division condition:

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