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Q.Calculate standard deviation of the following data.
Marks | 10-20 | 20-30 | 30-50 | 50-70 | 70-80
Frequency | 5 | 8 | 16 | 8 | 3

Himachal HpboseHPBOSE Himachal Class 11 (Commerce) 2024Subjective· 5mImportance★★★★★
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Standard deviation ≈ 17.17 (mean = 40.5).

We use the class mid-points (x) and frequencies (f). The classes have unequal widths, but the standard deviation is computed from mid-points regardless.

ClassMid-point xffx
10-2015575
20-30258200
30-504016640
50-70608480
70-80753225
TotalΣf = 40Σfx = 1620

Step 1 — Mean = Σfx/Σf = 1620/40 = 40.5.

Step 2 — Deviations d = x − mean, and f·d²:

  • x=15: d = −25.5, d² = 650.25, f·d² = 3251.25
  • x=25: d = −15.5, d² = 240.25, f·d² = 1922.00
  • x=40: d = −0.5, d² = 0.25, f·d² = 4.00 …

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