Skip to content
Question of 98

Q.If 100 calories of heat are added to a system and a work of 50 calories is done on the system. Calculate the internal energy change of the system.

Himachal HpboseHPBOSE Himachal Pradesh Class 11 Board Exam 2026Subjective· 2mImportance★★★★★
0% · 0/98 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

ΔU = q + w = 100 cal + 50 cal = 150 calories.

By the first law of thermodynamics (using the IUPAC sign convention, where heat absorbed by the system and work done on the system are both taken as positive):

ΔU=q+w\Delta U = q + w

Given:

  • Heat added to the system, q = +100 cal (heat flows INTO the system)
  • Work done ON the system, w = +50 cal (work is done on the system, not by it)

Substituting:

ΔU=100+50=150 cal\Delta U = 100 + 50 = 150 \text{ cal}

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.