Skip to content
Question of 98

Q.In a process, 701 j of heat is absorbed by a system and 394 j of work is done by the system. What is the change in internal energy for the process.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2026Subjective· 2mImportance★★★★★
0% · 0/98 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

By the first law, Delta U = q + w; with q = +701 J (heat absorbed) and w = -394 J (work done BY the system), Delta U = +307 J.

The first law of thermodynamics states:

Delta U = q + w

where (using the IUPAC sign convention):

  • q is positive when heat is absorbed BY the system, negative when heat is released.
  • w is positive when work is done ON the system, negative when work is done BY the system.

Given:

  • Heat absorbed by the system, q = +701 J …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.