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Q.Using elementary operations, find the inverse of the matrix [[2, 1], [7, 4]].

Himachal HpboseHPBOSE Plus Two Board 2024Subjective· 3mImportance★★★★★
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Reducing [A | I] to [I | A⁻¹] using row operations gives A⁻¹ = [[4, −1], [−7, 2]].

Let A=(2174)A = \begin{pmatrix}2 & 1\\ 7 & 4\end{pmatrix}. Write A=IAA = IA:

(2174)=(1001)A\begin{pmatrix}2 & 1\\ 7 & 4\end{pmatrix} = \begin{pmatrix}1 & 0\\ 0 & 1\end{pmatrix} A

R1→R1−3R2+…R_1 \to R_1 - 3R_2 + \dots Instead use a cleaner path: R2→R2−3R1R_2 \to R_2 - 3R_1:

(2111)=(10−31)A\begin{pmatrix}2 & 1\\ 1 & 1\end{pmatrix} = \begin{pmatrix}1 & 0\\ -3 & 1\end{pmatrix} A (since 7−3(2)=17-3(2)=1, 4−3(1)=14-3(1)=1).

R1→R1−R2R_1 \to R_1 - R_2: (1011)=(4−1−31)A\begin{pmatrix}1 & 0\\ 1 & 1\end{pmatrix} = \begin{pmatrix}4 & -1\\ -3 & 1\end{pmatrix} A.

R2→R2−R1R_2 \to R_2 - R_1: (1001)=(4−1−72)A\begin{pmatrix}1 & 0\\ 0 & 1\end{pmatrix} = \begin{pmatrix}4 & -1\\ -7 & 2\end{pmatrix} A.

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