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Question 114 of 121

Q.If A=[x000y000z]A = \begin{bmatrix}x & 0 & 0\\0 & y & 0\\0 & 0 & z\end{bmatrix} is a non singular matrix, then find A−1A^{-1} by elementary row transformations. Hence write the inverse of [20001000−1]\begin{bmatrix}2 & 0 & 0\\0 & 1 & 0\\0 & 0 & -1\end{bmatrix}

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2023Subjective· 2mImportance★★★★★
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Write A=IAA=IA and reduce AA to II using row operations R1→1xR1R_1\to\frac1xR_1 etc.

Write A=IAA=IA:

[x000y000z]=[100010001]A\begin{bmatrix}x&0&0\\0&y&0\\0&0&z\end{bmatrix}=\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}A

Apply R1→1xR1, R2→1yR2, R3→1zR3R_1\to\frac1xR_1,\ R_2\to\frac1yR_2,\ R_3\to\frac1zR_3:

[100010001]=[1/x0001/y0001/z]A\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}=\begin{bmatrix}1/x&0&0\\0&1/y&0\\0&0&1/z\end{bmatrix}A

So A−1=[1/x0001/y0001/z]A^{-1}=\begin{bmatrix}1/x&0&0\\0&1/y&0\\0&0&1/z\end{bmatrix}.

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