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Q.A solenoid of length 0.5 m has a radius of 1 cm and is made up of 500 turns. It carries a current of 5 A. What is the magnitude of the magnetic field inside the solenoid? OR What is Inductive reactance? Show that resistance offered by a ideal inductor to flow of direct current is zero.

Himachal HpboseHPBOSE Plus Two Board 2025Subjective· 2mImportance★★★★★
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Use B=μ0nIB = \mu_0 n I for a long solenoid, with nn = turns per unit length.

Given: length L=0.5 mL = 0.5\,m, number of turns N=500N = 500, current I=5 AI = 5\,A.

Turns per unit length: n=NL=5000.5=1000 turns/mn = \dfrac{N}{L} = \dfrac{500}{0.5} = 1000\ \text{turns/m}

Magnetic field inside a long solenoid:

B=μ0nI=(4π×10−7)×1000×5B = \mu_0 n I = (4\pi\times10^{-7})\times1000\times5

B=4π×10−7×5000=2π×10−3 T≈6.28×10−3 TB = 4\pi\times10^{-7}\times5000 = 2\pi\times10^{-3}\,T \approx 6.28\times10^{-3}\,T

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