Q.The solubility product of Al (OH)3 is 2.7 × 10^-11. Calculate its solubility in gL^-1 and also find out pH of this solution. (Atomic mass of Al = 27 u).

Solubility Product Constant: From Intuition to Precision

Imagine you drop a pinch of salt into a glass of water. The salt crystals disappear — they dissolve. But what if you keep adding salt, spoonful after spoonful? At some point, the water can't hold any more; the extra salt just sits at the bottom, undissolved. That's a saturated solution — the maximum amount of solute has dissolved at that temperature.

Now, here's the key question: even in that saturated solution, is everything static? Not at all. At the microscopic level, salt ions are constantly leaving the solid crystal and entering the solution (dissolving), while other ions in solution bump into the crystal and stick back (precipitating). At saturation, these two processes happen at exactly the same rate. The system is in dynamic equilibrium.

The Intuition: A Crowded Dance Floor

Think of a dance hall with a capacity limit. The "dancers" are ions (like Na⁺ and Cl⁻ from table salt). The dance floor is the solution. When the floor is empty, dancers easily find space — dissolution is fast. As more dancers arrive, they start bumping into each other and some leave the floor (precipitate). At the maximum capacity, the number of dancers entering equals the number leaving. That equilibrium number of dancers is what we call solubility.

But here's the twist: for many salts, the "dancers" come in different types — say, positive ions and negative ions. The equilibrium isn't just about the total number; it's about the product of their concentrations. Why product? Because the chance of a positive and a negative ion meeting to form a solid depends on both their concentrations. If you double the concentration of positive ions, the chance of a collision doubles. If you double both, it quadruples.

That product — at equilibrium, for a saturated solution — is a constant. That's the solubility product constant, $K_{sp}$.

The Precise Statement

For a sparingly soluble salt that dissociates in water as:

the solubility product constant is defined as:

where the square brackets denote molar concentrations (mol/L) at saturation (equilibrium with the solid).

What $K_{sp}$ Tells You

• Small $K_{sp}$ (e.g., $10^{-30}$): The salt is very insoluble. Only a tiny amount dissolves.
• Large $K_{sp}$ (e.g., $10^{-2}$): The salt is relatively soluble.
• $K_{sp}$ is temperature-dependent — always quote the temperature (usually 25°C).

A Concrete Example: Silver Chloride

Silver chloride, AgCl, is a classic sparingly soluble salt. Its dissolution:

The $K_{sp}$ expression:

At 25°C, $K_{sp} = 1.8 \times 10^{-10}$. This tiny number means that in a saturated solution, the product of the two ion concentrations is only $1.8 \times 10^{-10}$.

If you know the solubility of AgCl is $s$ mol/L, then $[Ag^+] = s$ and $[Cl^-] = s$, so: …