Q.State and explain de-Broglie equation.
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Start your 14-day free trial to unlock the full solution →De Broglie's equation, lambda = h/(mv), gives the wavelength associated with any moving particle, unifying wave and particle behaviour of matter.
Statement: In 1924, Louis de Broglie proposed that just as light (traditionally considered a wave) shows particle-like behaviour (as photons), matter (traditionally considered particles) should also show wave-like behaviour. Every moving material particle has a wave associated with it, called the matter wave or de Broglie wave, whose wavelength is given by:
lambda = h / (m.v) = h / p
where h = Planck's constant (6.626 x 10^-34 J.s), m = mass of the particle, v = velocity, and p = m.v = momentum of the particle.
Derivation (by analogy): For a photon, Einstein's relation gives energy E = h.nu = h.c/lambda. Also, from Einstein's mass-energy relation applied to a photon, E = m.c^2, so equating: m.c^2 = h.c/lambda, which gives lambda = h/(m.c). De Broglie generalised this by replacing the photon's speed c with the general particle velocity v, giving lambda = h/(m.v) for any moving particle.
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