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Exercise 2.2 · Q5

Q.Let A={1,2,3,4,6}A = \{1, 2, 3, 4, 6\}. Let RR be the relation on AA defined by {(a,b):a,b∈A, b is exactly divisible by a}\{(a, b) : a, b \in A,\ b\text{ is exactly divisible by }a\}.

(i) Write RR in roster form
(ii) Find the domain of RR
(iii) Find the range of RR.
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The relation RR consists of all ordered pairs (a,b)(a,b) from AA where aa divides bb exactly. Writing it in roster form gives 10 pairs; the domain is {1,2,3,4,6}\{1,2,3,4,6\} and the range is {1,2,3,4,6}\{1,2,3,4,6\}.

The key idea is simple: "b is exactly divisible by a" means a divides b with no remainder — in other words, b is a multiple of a. Since both numbers come from the same small set A={1,2,3,4,6}A = \{1,2,3,4,6\}, we can check every possible pair.

A Relation Arrow Diagram helps here. Imagine drawing two copies of set AA, one on the left (for the first element aa) and one on the right (for bb). Draw an arrow from aa to bb whenever aa divides bb. For example, 1 divides everything, so arrows go from 1 to every number. 2 divides 2, 4, and 6, so arrows go from 2 to those. 3 divides 3 and 6. 4 divides only 4. 6 divides only 6. This visual instantly shows you all the pairs — and also makes the domain and range obvious: the domain is the set of all left-side numbers that have at least one arrow leaving them, and the range is the set of all right-side numbers that have at least one arrow arriving.

Let’s now write it step by step.

  1. List all pairs (a,b)(a,b) where aa divides bb.

    For each aa in AA, find every bb in AA such that b÷ab \div a is an integer (i.e., bb is a multiple of aa).

    • a=1a = 1: every bb works, so (1,1),(1,2),(1,3),(1,4),(1,6)(1,1), (1,2), (1,3), (1,4), (1,6).
    • a=2a = 2: bb must be a multiple of 2 from AA → 2,4,62,4,6 → (2,2),(2,4),(2,6)(2,2), (2,4), (2,6).
    • a=3a = 3: multiples of 3 in AA are 3,63,6 → (3,3),(3,6)(3,3), (3,6).
    • a=4a = 4: multiples of 4 in AA are just 44 → (4,4)(4,4).
    • a=6a = 6: multiples of 6 in AA are just 66 → (6,6)(6,6).

    So R={(1,1),(1,2),(1,3),(1,4),(1,6),(2,2),(2,4),(2,6),(3,3),(3,6),(4,4),(6,6)}R = \{(1,1), (1,2), (1,3), (1,4), (1,6), (2,2), (2,4), (2,6), (3,3), (3,6), (4,4), (6,6)\}.

    Watch out

    A common mistake is to forget that a number is always divisible by itself. Every aa gives at least (a,a)(a,a) — don’t leave those out.

  2. Find the domain of RR. …

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