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Exercise 13.2 · Q9
Q.

Find the mean, variance and standard deviation using short-cut method.

Height in cmsNo. of children
70-753
75-804
80-857
85-907
90-9515
95-1009
100-1056
105-1106
110-1153
Jammu Kashmir JkboseTextbookSubjective· 5mImportance★★★★★est
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Mean =93= 93 cm, variance ≈105.58\approx 105.58 cm², and standard deviation ≈10.28\approx 10.28 cm.

Short-cut (step-deviation) method

Class marks xix_i run 72.5,77.5,…,112.572.5, 77.5, \dots, 112.5. Take A=92.5A = 92.5, h=5h = 5, and ui=xi−Ahu_i = \dfrac{x_i - A}{h}. Then

xˉ=A+h⋅∑fiuiN,σ2=h2[∑fiui2N−(∑fiuiN)2].\bar{x} = A + h\cdot\frac{\sum f_i u_i}{N}, \qquad \sigma^2 = h^2\left[\frac{\sum f_i u_i^2}{N} - \left(\frac{\sum f_i u_i}{N}\right)^2\right].

Step-by-step solution

Heightfif_ixix_iuiu_ifiuif_i u_ifiui2f_i u_i^2
70-75372.5−4-4−12-1248
75-80477.5−3-3−12-1236
80-85782.5−2-2−14-1428
85-90787.5−1-1−7-77
90-951592.5000
95-100997.5199
100-1056102.521224
105-1106107.531854
110-1153112.541248
Total606254

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