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Q.State law of equipartition of energy.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2022Subjective· 2mImportance★★★★★
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In thermal equilibrium, every degree of freedom of a molecule (each independent quadratic term in its energy) gets an equal average share of energy = (1/2) kT.

The law of equipartition of energy states that for a system in thermal equilibrium at absolute temperature T, the total energy is equally distributed among all the degrees of freedom of its constituent molecules. Each degree of freedom that contributes a quadratic term to the total energy (e.g. (1/2)mv_x^2 for translational motion along x, or (1/2)I*omega^2 for rotation about an axis) has an average energy of:

(1/2) k T

where k is Boltzmann's constant. For a molecule with f total degrees of freedom (translational + rotational, and, at high enough temperature, vibrational -- each vibrational mode counts as 2 since it has both a kinetic and a potential energy term), the total average energy per molecule is:

E = (f/2) k T

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