Q.State law of equipartition of energy.
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →In thermal equilibrium, every degree of freedom of a molecule (each independent quadratic term in its energy) gets an equal average share of energy = (1/2) kT.
The law of equipartition of energy states that for a system in thermal equilibrium at absolute temperature T, the total energy is equally distributed among all the degrees of freedom of its constituent molecules. Each degree of freedom that contributes a quadratic term to the total energy (e.g. (1/2)mv_x^2 for translational motion along x, or (1/2)I*omega^2 for rotation about an axis) has an average energy of:
(1/2) k T
where k is Boltzmann's constant. For a molecule with f total degrees of freedom (translational + rotational, and, at high enough temperature, vibrational -- each vibrational mode counts as 2 since it has both a kinetic and a potential energy term), the total average energy per molecule is:
E = (f/2) k T
…
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.