Q.If there were only one type of charge in the universe, then
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Gauss Law
Gauss's Law is a shortcut. Instead of adding up the Coulomb contribution of every charge — a nightmare of vectors and integrals — it lets you read the field straight off the symmetry of a problem. The whole idea rests on one quantity: electric flux.
Flux — field-lines counted through a surface. For a uniform field E crossing a flat area A, the flux is Φ = E·A = EA cosθ, where θ is the angle between the field and the normal to the surface. Picture the field as a bundle of lines; flux is how many pierce the surface. When E is edge-on (θ = 90°) nothing passes through and Φ = 0; when E is ⊥ to the surface (θ = 0) the count is maximal. For a closed surface, Φ is the net number of lines leaving it — lines that enter and exit cancel.
The law itself. Gauss's law states that the net flux out of any closed surface depends only on the charge trapped inside:
Φ = q_enclosed / ε₀.
Two consequences do most of the work. First, only enclosed charge counts — a charge outside sends as many lines in as out, so its net contribution is exactly zero. Second, the surface's shape is irrelevant; move the charge around inside or deform the surface, and Φ never changes.
Why symmetry makes it powerful. By itself Φ = q/ε₀ has E buried in an integral. It becomes a tool only when you pick a Gaussian surface matched to the symmetry — one where E is constant and everywhere either ⊥ to the surface (so Φ = EA) or ∥ to it (contributing nothing). Then E slides out and you solve in one line. This works for exactly three geometries:
1 — Infinite line charge (linear density λ). Use a coaxial cylinder: E = λ / 2πε₀r, falling off as ∝ 1/r.
2 — Infinite sheet (surface density σ). Use a pillbox pierced through the sheet: E = σ / 2ε₀ — uniform and completely independent of distance. The field near a large charged plane simply doesn't weaken as you step back. …
Why this formula?
Gauss's Law: Why It Holds
Gauss's Law is one of the four Maxwell's equations and a cornerstone of electromagnetism. Let's build the understanding from the ground up — not just the formula, but the why.
1. The Core Idea: Flux as "Flow" of Field
Imagine an electric field E passing through a small patch of area dA. The electric flux through that patch is:
dΦE=E⋅dA=EdAcosθ
where θ is the angle between E and the outward normal to the surface.
Why this definition?
- If E is perpendicular to the surface (θ=0), maximum field "flows through".
- If E is parallel (θ=90∘), no flux — the field just slides along the surface.
Total flux through a closed surface S is:
ΦE=∮SE⋅dA
2. The Key Insight: Flux Depends Only on Enclosed Charge
Consider a single point charge +q at the centre of a spherical surface of radius r.
- By Coulomb's law, at every point on the sphere: E=4πε01r2q, radially outward.
- The area vector dA is also radially outward.
- So E⋅dA=EdA everywhere.
The total flux:
ΦE=∮EdA=E∮dA=(4πε01r2q)(4πr2)=ε0q
Notice: The r2 cancels! The flux is independent of the radius.
3. Why Shape Doesn't Matter
Now, what if the surface is not spherical but any closed shape enclosing the charge?
- Draw a small cone from the charge to the surface.
- The flux through a patch dA at distance r is dΦ=4πε01r2qcosθdA.
- But r2cosθdA is exactly the solid angle dΩ subtended by dA at the charge.
So dΦ=4πε0qdΩ.
Integrating over the entire closed surface: ∮dΩ=4π (total solid angle around a point).
Hence:
ΦE=4πε0q⋅4π=ε0q
Result: For any closed surface enclosing q, the flux is ε0q.
4. Multiple Charges: Superposition
If there are many charges q1,q2,…,qn inside the surface, the total electric field is the vector sum of individual fields:
E=E1+E2+⋯+En
Flux is linear: …
Gauss's law, ∮SE⋅dS=qenc/ε0, fixes the net flux through a closed surface entirely by the charge enclosed, and this is true whether the universe has one kind of charge or two. A charge lying outside the surface contributes equal entering and leaving flux, so the net is zero; a charge q inside gives q/ε0. Flux is always a well-defined integral, and it can certainly be zero. …
Gauss's law ∮SE⋅dS=qenc/ε0 ties the net flux only to the enclosed charge, and holds regardless of how many kinds of charge exist. A charge outside gives zero net flux; a charge q inside gives q/ε0. Correct: (b) and (d).
Concept understanding
Gauss's law is a geometric consequence of the inverse-square Coulomb field. For any closed surface,
∮SE⋅dS=ε0qenc.
Nothing in its derivation requires the existence of both positive and negative charge — it depends only on the 1/r2 field and the solid-angle geometry of a closed surface.
Testing each option
- (a) claims the flux is never zero. This is false: the field lines from a charge lying outside the surface enter one side and leave the other, so their contributions cancel and the net flux vanishes.
- (b) If the charge is outside the surface, qenc=0, so ∮SE⋅dS=0. True. …
Concept: Electric Field of a Point Charge
If there were only one type of charge in the universe, the electric field would still exist exactly as we know it — but with a crucial simplification: there would be no attraction, only repulsion (or only attraction, depending on which type we imagine).
Method: Coulomb’s Law + Superposition (Single Charge Case)
Since there is only one type of charge, every other charge experiences a force that is always repulsive (if we take the existing charge to be positive) or always attractive (if negative). The field lines would never terminate on an opposite charge — they would simply radiate outward to infinity.
Steps:
-
Identify the source charge
Let the single type of charge be +Q (positive). Place it at the origin.
-
Apply Coulomb’s Law for a test charge
The force on a test charge +q at position r is:
F=4πε01r2Qqr^
Since both charges are the same sign, the force is repulsive (away from Q).
- Define the electric field The electric field at r due to Q is:
E(r)=qF=4πε01r2Qr^
- Interpret the field lines
- Direction: Radially outward from Q (if Q>0).
- No termination: Field lines go to infinity because there is no opposite charge to end on.
- Density: Decreases as 1/r2, consistent with the inverse-square law. …
Here are the common mistakes students make when reasoning about a universe with only one type of charge, along with how to avoid each.
Mistake 1: Assuming Electric Fields Still Exist as We Know Them
- The mistake: Students often continue to draw field lines starting from the single charge type and ending at infinity, or they assume that field lines can still "terminate" somewhere. They forget that field lines only begin on positive charges and end on negative charges.
- How to avoid: Recall the definition of an electric field line: it starts at a positive charge and ends at a negative charge. If only one type exists, field lines cannot terminate. They must either go to infinity or form closed loops. In a universe with only one charge type, the net flux through any closed surface is non-zero (by Gauss's law), so the field cannot be zero everywhere. The correct picture is that field lines radiate outward (if the charge is positive) and never end — they extend to infinity.
Mistake 2: Forgetting Gauss’s Law Implications
- The mistake: Students think that if there is only one charge, the electric field must be zero everywhere because there is no opposite charge to "balance" it. They ignore that Gauss’s law (∮E⋅dA=ε0Qenc) still holds. A single charge produces a non-zero field.
- How to avoid: Apply Gauss’s law directly. For a single point charge q, the field at distance r is E=4πε01r2q, regardless of whether other charges exist. The field does not vanish — it simply diverges from the charge. The only way to have zero field everywhere is if the total charge in the universe is zero.
Mistake 3: Confusing "One Type of Charge" with "One Charge"
- The mistake: Students interpret "one type of charge" as meaning there is only a single charge particle in the entire universe. They then try to apply Coulomb’s law between two identical charges, but there is no second charge to interact with.
- How to avoid: "One type of charge" means all charges have the same sign (all positive or all negative). There can be many such charges. The key point is that unlike charges do not exist, so there is no attraction — only repulsion. The universe would be filled with repelling charges, and no stable neutral matter could form.
Mistake 4: Assuming Electric Forces Can Still Cancel
- The mistake: Students think that multiple charges of the same sign can arrange themselves so that the net force on a test charge is zero (like in a neutral atom). They forget that without opposite charges, there is no possibility of cancellation — all forces are repulsive.
- How to avoid: Realize that in our universe, cancellation happens because positive and negative charges can coexist. With only one sign, any configuration of charges will produce a net repulsive force on a test charge of the same sign. The only way to have zero net force is if the test charge is infinitely far away or if the charges are arranged in a symmetric pattern (e.g., at the center of a uniformly charged sphere), but even then, the field inside a conductor would be zero only if charges can move — and they would all repel to the surface. …
- JKBOSE Class 12 Annual Regular Examination 2026Set SZ1 markMCQQ.The S.I Unit of electric flux is(a) N-m^2/C(b) Volt-metre(c) Both of them(d) None of them
›Reveal solutionSolution
Electric flux ΦE=E⋅A has SI unit N·m2/C, and N·m2/C is numerically and dimensionally identical to V·m — so both listed units are correct descriptions of the same quantity.
Concept. Electric flux through a surface is defined as
ΦE=E⋅A=EAcosθ
Using E in N/C. Since the SI unit of electric field is newton per coulomb (N/C), the unit of flux works out to
N/C×m2=N⋅m2/C
Using E in V/m. Electric field can equally be written in volt per metre (V/m), because 1 V=1 J/C=1 N⋅m/C, so 1 V/m=1 N/C. Using this form,
V/m×m2=V⋅m
…
- JKBOSE Class 12 Annual Regular Examination 2021Set SZ1 markQ.Give S.I. unit of electric flux.
›Reveal solutionSolution
Electric flux is ΦE=E⋅A, so its unit is the unit of electric field times the unit of area.
Electric flux through a surface is defined as
ΦE=E⋅A=EAcosθ
where E is the electric field, A is the area vector (magnitude equal to the area, direction along the outward normal), and θ is the angle between E and A.
…
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