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Q.Atomic radius depends upon the mass number A as

(a) A^0
(b) A^1
(c) A^3
(d) A^1/3
Jammu Kashmir JkboseJKBOSE Class 12 Annual Regular Examination 2026MCQ· 1mImportance★★★★★
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Experiments (electron scattering) show nuclear radius follows R=R0A1/3R = R_0 A^{1/3}, with R0≈1.2 fmR_0 \approx 1.2\ \text{fm}, because nuclear density is essentially constant for all nuclei.

Concept. Since nuclear matter has (nearly) constant density ρ\rho for all nuclei, and mass is proportional to mass number AA (each nucleon has roughly the same mass), the nuclear volume must be proportional to AA:

V∝AV \propto A

Deriving the radius dependence. Treating the nucleus as a sphere of radius RR,

V=43πR3∝A  ⟹  R3∝A  ⟹  R∝A1/3V = \frac{4}{3}\pi R^3 \propto A \implies R^3 \propto A \implies R \propto A^{1/3}

This gives the well-known empirical formula

R=R0A1/3,R0≈1.2×10−15 m=1.2 fmR = R_0 A^{1/3}, \quad R_0 \approx 1.2\times 10^{-15}\ \text{m} = 1.2\ \text{fm}

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