Q.If and are the radii of atomic nuclei of mass numbers and respectively, then the value of is : (A) (B) (C) (D)
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Start your 14-day free trial to unlock the full solution →Nuclear radius scales as the cube root of mass number: . Taking the ratio gives .
The size of an atomic nucleus is not arbitrary. Experiments—particularly Rutherford scattering and later electron-scattering studies—revealed that nuclear radius follows a beautiful empirical law that connects it directly to how many nucleons (protons and neutrons) are packed inside.
The key insight is that nuclear matter has roughly constant density. Think of nucleons as incompressible spheres packed together: if you double the number of nucleons, you double the volume, not the radius. Since volume scales as , the radius must scale as the cube root of the number of nucleons.
where is the mass number (total nucleons) and is a constant.
Now let's find the ratio of the two nuclear radii.
- Write the radius for each nucleus For the nucleus with mass number :
For the nucleus with mass number :
- Form the ratio When we divide by , the constant cancels: …
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