Q.An object approaches a convergent lens from the left of the lens with a uniform speed 5 m/s and stops at the focus. The image
Concept understanding — Lens Maker's Formula
The Intuition: Why a Lens Bends Light
A lens works because light slows down when it enters glass. When a wavefront hits a curved surface at an angle, different parts of it slow down at different moments, and the wavefront bends. The stronger the curvature, the more it bends.
A lens has two surfaces. Each surface bends light by an amount that depends on its radius of curvature R and the refractive index n of the glass. The net bending — the focal length f — is the combined effect of both surfaces.
If you had a single spherical surface separating air from glass, its contribution to bending power is Rn−1. A lens has two such surfaces: light goes from air into glass at the first surface, then from glass back into air at the second. Because the two surfaces face opposite directions relative to the travelling light, their radii typically carry opposite signs.
This uses the New Cartesian Sign Convention (the one used in NCERT and CBSE): all distances are measured from the optical centre, and the direction the incident light travels in is taken as positive. So R is positive if the centre of curvature lies on the side the light is travelling towards (the outgoing side), and negative if it lies on the side the light is travelling from (the incident side).
The Precise Statement
For a thin lens (thickness negligible compared to the radii), the Lens Maker's Formula is:
f1=(n−1)(R11−R21)
where:
- f is the focal length of the lens (positive for converging, negative for diverging)
- n is the refractive index of the lens material relative to the surrounding medium (usually air)
- R1 is the radius of curvature of the first surface (the one light reaches first)
- R2 is the radius of curvature of the second surface
f1=(n−1)(R11−R21)
How to Apply It: A Worked Example
Take a biconvex lens made of glass (n=1.5) with both surfaces having the same radius of curvature magnitude, 20 cm.
Light travels left to right. The first surface bulges toward the incoming light, so its centre of curvature lies to the right of the surface — on the side the light is travelling towards. By the rule above, R1=+20 cm.
The second surface also bulges outward (away from the lens), so its centre of curvature lies to the left of that surface — on the side the light is travelling from. So R2=−20 cm.
Plug in:
f1=(1.5−1)(201−−201)=0.5×(201+201)=0.5×202=201
So f=+20 cm. Positive means converging — correct for a biconvex lens.
The most common mistake is getting the sign of R2 wrong. For a biconvex lens, R1 is positive and R2 is negative. For a biconcave lens, it's the reverse: R1 negative, R2 positive. Always sketch the lens and mark where each surface's centre of curvature actually sits.
Why the Formula Works (Brief Derivation)
The derivation applies the refraction-at-a-single-spherical-surface formula twice — once at each surface — and combines the results. For a thin lens, the image formed by the first surface acts as the object for the second surface.
Each surface contributes a "power" P=Rn2−n1, where n1 and n2 are the refractive indices on either side of that surface. At the first surface, n1=1 (air), n2=n (glass). At the second, n1=n, n2=1. Adding the two contributions (with the sign convention above) gives the Lens Maker's Formula.
When Does It Break?
The formula assumes:
- The lens is thin — thickness is negligible compared to the radii.
- Light rays are paraxial — close to the axis, making small angles with it.
- The surrounding medium is air on both sides (if not, n is replaced by the ratio nlens/nmedium).
In exam problems these assumptions almost always hold. The formula is the direct route from a lens's geometry to its focal length — and, by extension, to how strongly it converges or diverges light.
The Lens Maker's Formula is one of the most important derivations in the NCERT Class 12 Physics Ray Optics chapter, and 'lens maker's formula derivation class 12 physics' or 'lens maker's formula important questions' are frequently searched terms during board and JEE Main preparation. Getting the sign convention for R1 and R2 right, as shown here, is also the single most common source of error in JEE Main and NEET optics numericals.
Using v1−u1=f1 with u negative (real object, moving toward the lens at constant 5 m/s, so du/dt=+5 constant):
- Differentiating gives image velocity dtdv=(u+ff)2dtdu=(u+f)25f2 - positive, so the image moves away from the lens.
- As the object nears the focus (u→−f), (u+f)→0, so dv/dt→∞: the image speed diverges.
- A second differentiation shows d2v/dt2=−(u+f)350f2, which itself keeps growing rather than staying constant - the acceleration is non-uniform, not constant.
This rules out (a) uniform speed, (b) uniform acceleration, and (d) moving toward the lens.
Option (c): the image moves away from the lens with a non-uniform acceleration.
Because the lens equation is nonlinear, an object approaching a convergent lens at constant speed does not produce an image moving at constant speed - as the object nears the focus, the image's speed grows without bound and its acceleration keeps changing. This matches option (c): the image moves away from the lens with a non-uniform acceleration.
Setting up with the lens formula
Using the Cartesian sign convention (light travels left to right, distances measured from the lens): the object is real and to the left, so its distance u is negative; the image distance is v; the focal length of a convergent lens is f>0. The thin-lens formula is
v1−u1=f1⟹v=u+fuf.
The object starts far away (u→−∞) and moves toward the lens at a constant speed of 5 m/s, stopping right at the focus (u→−f).
Relating image velocity to object velocity
Differentiate the lens equation with respect to time:
−v21dtdv+u21dtdu=0⟹dtdv=(uv)2dtdu.
Since v/u=f/(u+f) (directly from the lens formula above),
dtdv=(u+ff)2dtdu.
The object moves toward the lens at constant speed 5 m/s: since u is negative and its magnitude is shrinking, u is increasing, so dtdu=+5 m/s (constant). So
dtdv=(u+f)25f2.
What happens as the object nears the focus
As u→−f (approaching from u<−f), the denominator (u+f)→0−, so (u+f)2→0+ and
dtdv⟶+∞.
The image velocity dv/dt is positive, meaning v increases - the (real) image moves further to the right, i.e. away from the lens, and its speed grows without bound as the object approaches the focus.
Is the acceleration uniform or not?
Differentiate once more:
dt2d2v=dtd[(u+f)25f2]=−(u+f)310f2⋅dtdu=−(u+f)350f2.
Since u<−f throughout the approach, (u+f)<0, so (u+f)3<0, making dt2d2v>0 - and, crucially, this second derivative itself keeps changing (it depends on (u+f)3, which is shrinking toward zero), so the image's acceleration is not constant - it is a genuinely non-uniform acceleration, growing ever larger as the object nears the focus.
Checking the options
- (a) "moves away with uniform speed 5 m/s" - false, the image speed diverges, it isn't constant or even equal to the object's speed.
- (b) "moves away with uniform acceleration" - false, we just showed d2v/dt2 is not constant.
- (c) "moves away with a non-uniform acceleration" - true, exactly as derived.
- (d) "moves towards the lens" - false, the (real) image moves away from the lens (to larger v), not towards it.
Option (c) is correct: the image moves away from the lens with a non-uniform (ever-increasing) acceleration, diverging in speed as the object approaches the focus.
Method: Differentiating the Lens/Mirror Equation to Find Image Velocity and Acceleration
This method solves problems where an object is IN MOTION and you must find how the image moves — its velocity, or whether that velocity/acceleration is uniform — without tracking the image position frame by frame.
Steps
Step 1: Write the governing equation with u and v as functions of time
For a lens (Cartesian sign convention, real object so u<0):
v1−u1=f1
Treat both u(t) and v(t) as time-dependent quantities linked by this one equation at every instant.
Step 2: Differentiate implicitly with respect to time
−v21dtdv+u21dtdu=0⇒dtdv=(uv)2dtdu
This directly relates the image's velocity to the object's velocity through the instantaneous ratio v/u — never assume the image moves at the same speed as the object.
Step 3: Express v/u purely in terms of known quantities
From the lens equation itself, v/u=f/(u+f), so substitute to get dv/dt as a function of u, f, and the (given, often constant) du/dt alone.
Step 4: Differentiate a second time to check whether the motion is uniform
Differentiate the Step-3 expression again with respect to time. If the result still depends on u (rather than collapsing to a constant), the image's acceleration is genuinely non-uniform — it changes as u changes, even though the object's own velocity was constant.
Step 5 (Applying to this problem): Examine the limiting behaviour
Check what happens as u approaches any special value in the problem (e.g. the focus, u→−f). If a factor like (u+f) appears in the denominator, the image's speed and/or acceleration can diverge there — this qualitative limiting check often answers a "uniform vs non-uniform" or "finite vs unbounded" question without needing a specific numeric answer.
- JKBOSE Class 12 Annual Regular Examination 2026Set SZ5 marksQ.What is Lens Maker's formula? Derive an expression for Lens Maker's formula for a convex lens. OR State Huygen's Principle. Derive laws of reflection from Huygen's Principle.
›Reveal solutionSolution
The Lens Maker's formula, f1=(μ−1)(R11−R21), is derived by applying single-surface refraction twice, once at each face of the lens. (OR alternative: Huygens' Principle constructs wavefronts from secondary wavelets, and can be used to derive the laws of reflection geometrically.)
Part 1: Lens Maker's Formula
What it is. The Lens Maker's formula relates a lens's focal length f to the refractive index μ of its material (relative to the surrounding medium) and the radii of curvature R1, R2 of its two spherical surfaces — it tells a lens manufacturer what curvatures are needed to grind a lens of a desired focal length.
Derivation for a thin convex lens. Consider a thin lens with two refracting surfaces of radii R1 (first surface, light hits this first) and R2 (second surface), made of material of refractive index μ, surrounded by air (index 1). Let a point object O on the principal axis form an image after refraction at each surface in turn.
Step 1 — Refraction at the first surface (radius R1), treating it alone (ignoring the second surface for now), forming a virtual intermediate image I1 at distance v1:
v1μ−u1=R1μ−1
Step 2 — Refraction at the second surface (radius R2): the image I1 from step 1 now acts as the object for this second refraction (light going from the denser lens medium μ back into air, index 1), forming the final image I at distance v:
v1−v1μ=R21−μ
Step 3 — Add the two equations (the μ/v1 terms cancel):
v1−u1=(μ−1)(R11−R21)
Step 4 — Apply the lens definition. When the object is at infinity (u→∞), the image forms at the focus (v=f), so v1−u1→f1. Substituting:
f1=(μ−1)(R11−R21)
This is the Lens Maker's formula, and it also leads to the general thin lens formula v1−u1=f1.
OR: Huygens' Principle and the Laws of Reflection
Huygens' Principle. Every point on a given wavefront (a surface of constant phase) acts as a source of new secondary wavelets, which spread out in all directions with the speed of the wave in that medium. The new wavefront at any later time is given by the forward "envelope" (common tangent surface) of all these secondary wavelets.
Deriving the laws of reflection. Consider a plane wavefront AB incident on a reflecting surface MN at angle of incidence i, with A striking the surface first while B is still travelling.
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By the time the wavelet from B reaches the surface at C (after time τ), the wavelet from A (already at the surface) has spread out as a hemisphere of radius vτ=AD (since it reflects back into the same medium, same speed v).
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The new reflected wavefront is the common tangent DC from this envelope.
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Comparing right triangles ABC and ADC (sharing hypotenuse AC): AD=BC=vτ (equal radii, both wavelets travelled for the same time in the same medium), and both are right triangles, so they are congruent, giving ∠BAC=∠DCA.
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Since ∠BAC is the angle of incidence i (angle between incident wavefront and surface) and ∠DCA is the angle of reflection r (angle between reflected wavefront and surface), this congruence directly gives:
i=r(angle of incidence = angle of reflection)
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Also, the incident ray, the reflected ray, and the normal at the point of incidence can be shown to lie in the same plane, completing the laws of reflection.
✓Final answerLens Maker's formula: f1=(μ−1)(R11−R21), derived by combining refraction at both surfaces of the lens. (OR: Huygens' Principle — every wavefront point emits secondary wavelets whose envelope gives the new wavefront; applying this to a reflecting surface proves angle of incidence = angle of reflection.)
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- JKBOSE Class 12 Annual Regular Examination 2023Set ANNUAL5 marksQ.Stating the assumptions made and convention of signs used, derive the lens maker's formula in case of a double convex lens. OR Define fringe width. Derive an expression for fringe width in Young's double slit experiment of interference of light.
›Reveal solutionSolution
The lens maker's formula, 1/f = (n21-1)(1/R1 - 1/R2), is derived by applying refraction at each of the two spherical surfaces of a thin lens in turn. (OR: Fringe width beta = lambdaD/d is derived from the path-difference condition for constructive/destructive interference in Young's double-slit experiment.)
Derivation of Lens Maker's Formula (for a thin double convex lens):
Assumptions: (i) The lens is thin, so the two refracting surfaces are close enough that the lateral displacement of the ray inside the lens can be neglected. (ii) Only paraxial rays (making small angles with the principal axis) are considered. (iii) The medium on both sides of the lens is the same (say, refractive index n1), and the lens material has refractive index n2.
Sign convention: All distances are measured from the pole/optical centre of the surface; distances measured in the direction of the incident light are taken positive, against it negative. For a double convex lens, the first surface (facing the incident light) is convex towards the object, so its radius R1 is positive; the second surface curves the other way, so its radius R2 is negative.
Consider a point object O on the principal axis. Let the first surface (radius R1) refract the light from the object; treating this surface alone, the image I1 formed (a virtual, intermediate image) obeys the single-surface refraction formula:
n2/v1 - n1/u = (n2 - n1)/R1 ... (i)
where u is the object distance and v1 is the image distance for the first surface alone.
This intermediate image I1 now acts as a virtual object for the second surface (radius R2), which refracts the ray back into the surrounding medium n1, forming the final real image I at distance v:
n1/v - n2/v1 = (n1 - n2)/R2 ... (ii)
Adding equations (i) and (ii), the n2/v1 and -n2/v1 terms cancel:
n1/v - n1/u = (n2-n1)/R1 + (n1-n2)/R2 = (n2-n1)*(1/R1 - 1/R2).
Dividing throughout by n1:
1/v - 1/u = (n2/n1 - 1)(1/R1 - 1/R2) = (n21 - 1)(1/R1 - 1/R2), where n21 = n2/n1 is the refractive index of the lens material relative to the surrounding medium.
Now, if the object is placed at infinity (u tends to infinity), the rays refracted by the lens converge (for a convex lens) to the principal focus, so v = f (the focal length). Putting u = infinity, 1/u = 0:
1/f = (n21 - 1)*(1/R1 - 1/R2).
This is the Lens Maker's Formula. It relates the focal length f of a thin lens to the refractive index of its material (relative to the surrounding medium) and the radii of curvature of its two surfaces, and is used by lens manufacturers to design a lens of a required focal length. For a double convex lens (R1 positive, R2 negative), (1/R1 - 1/R2) is positive, so f comes out positive - confirming it is a converging lens.
✓Final answer1/f = (n21 - 1)*(1/R1 - 1/R2), derived by applying single-surface refraction successively at the lens's two surfaces and adding the results (with u tending to infinity giving v = f).
OR: Fringe width and its derivation in Young's Double Slit Experiment (YDSE):
Fringe width (beta) is defined as the distance between any two consecutive bright fringes, or equivalently, between any two consecutive dark fringes, in an interference pattern.
Derivation: In Young's double-slit experiment, two narrow, coherent slits S1 and S2, separated by a small distance d, are illuminated by monochromatic light of wavelength lambda. A screen is placed at distance D from the slits (D much greater than d). Let O be the point on the screen directly in front of the midpoint of S1S2 (on the central axis), and let P be a point on the screen at distance x from O.
The path difference between the two waves arriving at P (from S1 and S2) is Delta = S2P - S1P ~ (d*x)/D (this follows from the geometry, using the approximation valid when D is much greater than d and x).
Condition for bright fringe (constructive interference): path difference = an integral multiple of lambda,
(dx_n)/D = nlambda => x_n = nlambdaD/d, where n = 0, +-1, +-2, ... gives the positions of the bright fringes (n=0 at the centre O).
Condition for dark fringe (destructive interference): path difference = an odd multiple of lambda/2,
(d*x_n)/D = (n + 1/2)*lambda => x_n = (n + 1/2)lambdaD/d.
Fringe width: The distance between two consecutive bright fringes (the nth and (n+1)th):
beta = x_(n+1) - x_n = (n+1)lambdaD/d - nlambdaD/d = lambda*D/d.
The same calculation for consecutive dark fringes also gives beta = lambdaD/d. So: beta = lambdaD/d,
which shows that all bright (and all dark) fringes are equally spaced, and the fringe width is directly proportional to the wavelength lambda and the slit-to-screen distance D, and inversely proportional to the slit separation d.
✓Final answerbeta = lambdaD/d, derived from the path-difference condition Delta = dx/D for constructive (n*lambda) and destructive ((n+1/2)lambda) interference, giving equally-spaced bright and dark fringes separated by lambdaD/d.
- JKBOSE Class 12 Annual Regular Examination 2021Set SZ5 marksQ.Derive Lens-Maker's formula for convex lens. Write the necessary sign convention used. OR State Huygen's wave principles. Use them to prove laws of refraction of light.
›Reveal solutionSolution
The lens-maker's formula relates a thin lens's focal length to its refractive index and the radii of curvature of its two surfaces, derived by applying single-surface refraction twice.
Sign convention (Cartesian, as used in NCERT): All distances are measured from the optical centre of the lens. Distances measured in the direction of the incident light are taken as positive; distances measured against the direction of incident light are taken as negative. Heights measured upward from the principal axis are positive, downward are negative. For a convex lens, if the centre of curvature of a surface lies on the outgoing-light side, its radius R is positive; if on the incoming-light side, R is negative.
Derivation of lens-maker's formula:
Consider a thin convex lens of refractive index n2 placed in a medium of refractive index n1, with surfaces of radii R1 and R2. Let an object be at O on the principal axis.
Refraction at the first surface (radius R1) forms an image at I1 (treating the second surface as absent), using the single spherical refracting surface formula:
v1n2−un1=R1n2−n1
Refraction at the second surface (radius R2): the image I1 from the first surface now acts as a virtual object for the second surface, forming the final image at I (at distance v):
vn1−v1n2=R2n1−n2
Adding these two equations (the n2/v1 terms cancel):
vn1−un1=(n2−n1)(R11−R21)
Dividing throughout by n1:
v1−u1=(n1n2−1)(R11−R21)=(n21−1)(R11−R21)
When the object is at infinity (u→∞), the image forms at the focus, v=f, giving the general lens formula v1−u1=f1, so:
f1=(n21−1)(R11−R21)
where n21=n2/n1 is the refractive index of the lens material relative to the surrounding medium.
OR — Huygens' principle and laws of refraction:
Huygens' wave principle: Every point on a given wavefront (locus of points vibrating in phase) acts as a source of new secondary wavelets, which spread out in all directions with the speed of the wave in that medium. The new (secondary) wavefront at any later instant is the surface tangent (envelope) to all these secondary wavelets.
Derivation of Snell's law using Huygens' construction:
Consider a plane wavefront AB incident on a plane interface XY separating medium 1 (speed v1) from medium 2 (speed v2), making angle of incidence i with the normal. Let the time taken for the wavelet from B to reach the interface at C be τ, so BC=v1τ.
During this same time τ, the secondary wavelet from A (which reached the interface first) spreads into medium 2 with radius AD=v2τ. The new refracted wavefront is the tangent CD from C to this wavelet.
From the right triangle ABC: sini=ACBC=ACv1τ.
From the right triangle ACD (with r = angle of refraction): sinr=ACAD=ACv2τ.
Dividing these:
sinrsini=v2v1
Since refractive index n=c/v, we have v1=c/n1 and v2=c/n2, so v2v1=n1n2, giving
n1sini=n2sinr
which is Snell's law of refraction. (The incident ray, refracted ray, and normal are all seen to lie in the plane of incidence from this construction, verifying the first law of refraction too.)
✓Final answerLens-maker's formula: f1=(n21−1)(R11−R21) (Cartesian sign convention, distances from optical centre, positive along incident-light direction). Huygens' construction gives Snell's law: n1sini=n2sinr.
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