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Exercises · 6.41

Q.The concentration of hydrogen ion in a sample of soft drink is 3.8 × 10⁻³ M. What is its pH?

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pH is the negative logarithm (base 10) of the hydrogen ion concentration. For [H+]=3.8×10−3 M[H^+] = 3.8 \times 10^{-3} \, \text{M}, the pH is approximately 2.42.

The pH scale is a convenient way to express the acidity of a solution. Instead of working with very small numbers like 3.8×10−33.8 \times 10^{-3} M, we compress the range into a simple number between 0 and 14 (for most aqueous solutions). The key is that pH is a logarithmic scale, not a linear one. A change of 1 pH unit means a tenfold change in hydrogen ion concentration.

The definition is straightforward:

pH=−log⁡10[H+]\text{pH} = -\log_{10} [H^+]

The negative sign ensures that most pH values are positive (since [H+][H^+] is usually less than 1 M). The logarithm base 10 tells us the power of 10 in the concentration.

Let’s work through the calculation step by step.

  1. Write down the given concentration.

    We have [H+]=3.8×10−3[H^+] = 3.8 \times 10^{-3} M.

  2. Apply the pH formula.

pH=−log⁡10(3.8×10−3)\text{pH} = -\log_{10} (3.8 \times 10^{-3})

  1. Use the logarithm product rule. The logarithm of a product is the sum of the logarithms:

log⁡10(a×b)=log⁡10a+log⁡10b\log_{10} (a \times b) = \log_{10} a + \log_{10} b

So:

log⁡10(3.8×10−3)=log⁡10(3.8)+log⁡10(10−3)\log_{10} (3.8 \times 10^{-3}) = \log_{10} (3.8) + \log_{10} (10^{-3})

  1. Evaluate each term separately.

    • log⁡10(10−3)=−3\log_{10} (10^{-3}) = -3 (since 10−310^{-3} is exactly 1010 raised to the power −3-3).
    • log⁡10(3.8)\log_{10} (3.8) is not an integer. Using a calculator or logarithm table: log⁡10(3.8)≈0.5798\log_{10} (3.8) \approx 0.5798.
  2. Add them together.

log⁡10(3.8×10−3)≈0.5798+(−3)=−2.4202\log_{10} (3.8 \times 10^{-3}) \approx 0.5798 + (-3) = -2.4202

  1. Apply the negative sign from the pH definition.

pH=−(−2.4202)=2.4202\text{pH} = -(-2.4202) = 2.4202

  1. Round to an appropriate number of decimal places. …

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