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Chemistry · Ch 10 — Hydrocarbons

Properties

10.5.5

Properties

Physical Properties

Aromatic hydrocarbons are non-polar molecules. This non-polar nature governs nearly all their physical behaviour. They are usually colourless liquids or solids at room temperature, and they carry a characteristic aroma — the word "aromatic" itself comes from this property.

You are already familiar with naphthalene balls, which are used in toilets and for preserving clothes. Naphthalene has a strong, unique smell and acts as a moth repellent. This is a practical everyday example of an aromatic hydrocarbon in use.

Because they are non-polar, aromatic hydrocarbons are immiscible with water (like oil and water). However, they dissolve readily in organic solvents such as ether, benzene itself, or carbon tetrachloride. When burned, they produce a sooty flame due to their high carbon content — the carbon atoms do not get fully oxidised and appear as black soot.

Chemical Properties

The chemistry of arenes (another name for aromatic hydrocarbons) is dominated by one type of reaction: electrophilic substitution. The benzene ring is rich in π\pi electrons, making it attractive to electron-seeking species (electrophiles). Under normal conditions, this is the characteristic reaction.

However, under special, more vigorous conditions, arenes can also undergo two other types of reactions:

  • Addition reactions — where the ring's double bonds are broken and atoms add across them.
  • Oxidation reactions — where the ring is burned or otherwise oxidised.

Electrophilic Substitution Reactions

The common electrophilic substitution reactions of arenes are nitration, halogenation, sulphonation, Friedel-Crafts alkylation, and Friedel-Crafts acylation. In every case, the attacking reagent is an electrophile, denoted as E+\text{E}^+.

Note

The general pattern

In all these reactions, a hydrogen atom on the benzene ring is replaced by the electrophile. The overall reaction is:

C6H6+E+⟶C6H5E+H+\text{C}_6\text{H}_6 + \text{E}^+ \longrightarrow \text{C}_6\text{H}_5\text{E} + \text{H}^+

(i) Nitration

A nitro group (−NO2-\text{NO}_2) is introduced into the benzene ring. This is done by heating benzene with a mixture of concentrated nitric acid (HNO3\text{HNO}_3) and concentrated sulphuric acid (H2SO4\text{H}_2\text{SO}_4). This mixture is called the nitrating mixture.

C6H6+HNO3→conc. H2SO4ΔC6H5NO2+H2O\text{C}_6\text{H}_6 + \text{HNO}_3 \xrightarrow[\text{conc. H}_2\text{SO}_4]{\Delta} \text{C}_6\text{H}_5\text{NO}_2 + \text{H}_2\text{O}

Nitrobenzene

Diagram eq-9.72-nitration-nitrobenzene-9.5.5Nitration of benzene: heating with a nitrating mixture of concentrated HNO3 and concentrated H2SO4 at 323–333 K replaces one ring hydrogen with a nitro group, giving nitrobenzene (equation 9.72).
Fig. eq-9.72-nitration-nitrobenzene-9.5.5 — Nitration of benzene: heating with a nitrating mixture of concentrated HNO3 and concentrated H2SO4 at 323–333 K replaces one ring hydrogen with a nitro group, giving nitrobenzene (equation 9.72).

Equation 9.72 — nitration: benzene heated with the nitrating mixture (concentrated HNOX3\ce{HNO3} + concentrated HX2SOX4\ce{H2SO4}) at 323–333 K gives nitrobenzene and water. The attacking electrophile …

(ii) Halogenation

Arenes react with halogens (like Cl2\text{Cl}_2 or Br2\text{Br}_2) in the presence of a Lewis acid catalyst, such as anhydrous FeCl3\text{FeCl}_3, FeBr3\text{FeBr}_3, or AlCl3\text{AlCl}_3, to yield haloarenes.

C6H6+Cl2→anhyd. FeCl3C6H5Cl+HCl\text{C}_6\text{H}_6 + \text{Cl}_2 \xrightarrow{\text{anhyd. FeCl}_3} \text{C}_6\text{H}_5\text{Cl} + \text{HCl}

Chlorobenzene

Diagram eq-9.73-halogenation-chlorobenzene-9.5.5Halogenation of benzene: chlorine in the presence of anhydrous AlCl3 (a Lewis acid) substitutes one ring hydrogen, giving chlorobenzene and HCl (equation 9.73).
Fig. eq-9.73-halogenation-chlorobenzene-9.5.5 — Halogenation of benzene: chlorine in the presence of anhydrous AlCl3 (a Lewis acid) substitutes one ring hydrogen, giving chlorobenzene and HCl (equation 9.73).

Equation 9.73 — halogenation: chlorine in the presence of anhydrous AlClX3\ce{AlCl3} (a Lewis acid) substitutes one ring hydrogen, givin …

(iii) Sulphonation

The replacement of a hydrogen atom by a sulphonic acid group (−SO3H-\text{SO}_3\text{H}) is called sulphonation. It is carried out by heating benzene with fuming sulphuric acid (oleum), which is sulphuric acid containing dissolved sulphur trioxide (SO3\text{SO}_3).

C6H6+H2SO4→ΔC6H5SO3H+H2O\text{C}_6\text{H}_6 + \text{H}_2\text{SO}_4 \xrightarrow{\Delta} \text{C}_6\text{H}_5\text{SO}_3\text{H} + \text{H}_2\text{O}

Benzenesulphonic acid

Diagram eq-9.74-sulphonation-benzenesulphonic-acid-9.5.5Sulphonation of benzene: heating with fuming sulphuric acid (oleum, H2SO4 containing SO3) replaces one ring hydrogen with the sulphonic acid group, giving benzene sulphonic acid (equation 9.74).
Fig. eq-9.74-sulphonation-benzenesulphonic-acid-9.5.5 — Sulphonation of benzene: heating with fuming sulphuric acid (oleum, H2SO4 containing SO3) replaces one ring hydrogen with the sulphonic acid group, giving benzene sulphonic acid (equation 9.74).

Equation 9.74 — sulphonation: heating benzene with fuming sulphuric acid (HX2SOX4\ce{H2SO4} containing SOX3\ce{SO3}) replaces a ring hydrogen with the −SOX3H\ce{-SO3H} group, …

(iv) Friedel-Crafts Alkylation Reaction

When benzene is treated with an alkyl halide (like R-Cl\text{R-Cl}) in the presence of anhydrous aluminium chloride (AlCl3\text{AlCl}_3), an alkylbenzene is formed.

C6H6+R-Cl→anhyd. AlCl3C6H5R+HCl\text{C}_6\text{H}_6 + \text{R-Cl} \xrightarrow{\text{anhyd. AlCl}_3} \text{C}_6\text{H}_5\text{R} + \text{HCl}

Diagram eq-9.75-fc-alkylation-toluene-9.5.5Friedel–Crafts alkylation: benzene and methyl chloride over anhydrous AlCl3 give toluene and HCl (equation 9.75).
Fig. eq-9.75-fc-alkylation-toluene-9.5.5 — Friedel–Crafts alkylation: benzene and methyl chloride over anhydrous AlCl3 give toluene and HCl (equation 9.75).

Equation 9.75 — Friedel–Crafts alkylation: benzene and methyl chloride over anhydrous AlClX3\ce{AlCl3} give toluene and HCl. The Lewis acid generates the attacki …

Diagram eq-9.76-fc-alkylation-ethylbenzene-9.5.5Friedel–Crafts alkylation: benzene and ethyl chloride over anhydrous AlCl3 give ethylbenzene and HCl (equation 9.76).
Fig. eq-9.76-fc-alkylation-ethylbenzene-9.5.5 — Friedel–Crafts alkylation: benzene and ethyl chloride over anhydrous AlCl3 give ethylbenzene and HCl (equation 9.76).

Equation 9.76 — the same Friedel–Crafts alkylation with ethyl chloride: benzene gives ethylbenzene and HCl over an …

Watch out

A common exam question

Why do we get isopropyl benzene on treating benzene with 1-chloropropane instead of n-propyl benzene?

The answer lies in the mechanism. The electrophile generated is a carbocation (R+\text{R}^+). The 1-chloropropane initially forms a primary carbocation (CH3CH2CH2+\text{CH}_3\text{CH}_2\text{CH}_2^+), which is unstable. It immediately rearranges to the more stable secondary carbocation (CH3CH+CH3\text{CH}_3\text{CH}^+\text{CH}_3) via a 1,2-hydride shift. This secondary carbocation then attacks the benzene ring, giving isopropyl benzene as the major product.

(v) Friedel-Crafts Acylation Reaction

The reaction of benzene with an acyl halide (like RCO-Cl\text{RCO-Cl}) or an acid anhydride in the presence of a Lewis acid (AlCl3\text{AlCl}_3) yields an acyl benzene (a ketone).

C6H6+RCO-Cl→anhyd. AlCl3C6H5COR+HCl\text{C}_6\text{H}_6 + \text{RCO-Cl} \xrightarrow{\text{anhyd. AlCl}_3} \text{C}_6\text{H}_5\text{COR} + \text{HCl}

Diagram eq-9.77-fc-acylation-acetophenone-9.5.5Friedel–Crafts acylation: benzene and acetyl chloride (CH3COCl) over anhydrous AlCl3 give acetophenone and HCl (equation 9.77).
Fig. eq-9.77-fc-acylation-acetophenone-9.5.5 — Friedel–Crafts acylation: benzene and acetyl chloride (CH3COCl) over anhydrous AlCl3 give acetophenone and HCl (equation 9.77).

Equation 9.77 — Friedel–Crafts acylation: benzene and acetyl chloride (CHX3COCl\ce{CH3COCl}) over anhydrous AlClX3\ce{AlCl3} (with heating) give acetophenone (methyl phenyl ketone) and HCl; the electrophil …

Diagram eq-9.78-fc-acylation-anhydride-9.5.5Friedel–Crafts acylation with an acid anhydride: benzene and acetic anhydride ((CH3CO)2O) over anhydrous AlCl3 give acetophenone and acetic acid (equation 9.78).
Fig. eq-9.78-fc-acylation-anhydride-9.5.5 — Friedel–Crafts acylation with an acid anhydride: benzene and acetic anhydride ((CH3CO)2O) over anhydrous AlCl3 give acetophenone and acetic acid (equation 9.78).

Equation 9.78 — Friedel–Crafts acylation with an acid anhydride: benzene and acetic anhydride (CHX3CO)X2O\ce{(CH3CO)2O} over anhydrous AlClX3\ce{AlCl3} give the same product, acetophenone, with ethanoic aci …

Further Substitution

If an excess of the electrophilic reagent is used, further substitution reactions can take place. Other hydrogen atoms on the benzene ring may also be successively replaced by the electrophile. For example, benzene treated with excess chlorine in the presence of anhydrous AlCl3\text{AlCl}_3 can be chlorinated all the way to hexachlorobenzene (C6Cl6\text{C}_6\text{Cl}_6).

C6H6+6Cl2→anhyd. AlCl3C6Cl6+6HCl\text{C}_6\text{H}_6 + 6\text{Cl}_2 \xrightarrow{\text{anhyd. AlCl}_3} \text{C}_6\text{Cl}_6 + 6\text{HCl}

Diagram eq-9.79-hexachlorobenzene-9.5.5With excess chlorine over anhydrous AlCl3 in the dark and cold, all six ring hydrogens of benzene are successively substituted, giving hexachlorobenzene (C6Cl6) and six HCl (equation 9.79).
Fig. eq-9.79-hexachlorobenzene-9.5.5 — With excess chlorine over anhydrous AlCl3 in the dark and cold, all six ring hydrogens of benzene are successively substituted, giving hexachlorobenzene (C6Cl6) and six HCl (equation 9.79).

Equation 9.79 — substitution taken to completion: with excess chlorine over anhydrous AlClX3\ce{AlCl3} in the dark and cold, all six ring hydrogens of benzene are successively replaced, giving hexachlorobenzene (CX6ClX6\ce{C6Cl6}) and six HCl. Note the ring itself is still aromati …

Mechanism of Electrophilic Substitution Reactions

According to experimental evidence, SE\text{S}_\text{E} (Substitution, Electrophilic) reactions proceed via three distinct steps:

  1. Generation of the electrophile (E+\text{E}^+)
  2. Formation of a carbocation intermediate (arenium ion)
  3. Removal of a proton from the carbocation intermediate
›Proof

Step-by-step mechanism

Step (a): Generation of the electrophile E+\text{E}^+

The Lewis acid catalyst (AlCl3\text{AlCl}_3, FeCl3\text{FeCl}_3) plays a crucial role here. It combines with the attacking reagent to generate the active electrophile.

  • For chlorination, alkylation, and acylation: Anhydrous AlCl3\text{AlCl}_3 (a Lewis acid) accepts a lone pair from the halogen in the reagent, forming a complex that then dissociates to give the electrophile.

    • Chlorination: Cl2+FeCl3→Cl++[FeCl4]−\text{Cl}_2 + \text{FeCl}_3 \rightarrow \text{Cl}^+ + [\text{FeCl}_4]^-
    • Alkylation: R-Cl+AlCl3→R++[AlCl4]−\text{R-Cl} + \text{AlCl}_3 \rightarrow \text{R}^+ + [\text{AlCl}_4]^-
    • Acylation: RCO-Cl+AlCl3→RCO++[AlCl4]−\text{RCO-Cl} + \text{AlCl}_3 \rightarrow \text{RCO}^+ + [\text{AlCl}_4]^- (the RCO+\text{RCO}^+ ion is called an acylium ion)
  • For nitration: The electrophile is the nitronium ion (NO2+\text{NO}_2^+). It is produced by a transfer of a proton from sulphuric acid to nitric acid. This is a simple acid-base equilibrium.

    Step I:

    HNO3+H2SO4⇌H2NO3++HSO4−\text{HNO}_3 + \text{H}_2\text{SO}_4 \rightleftharpoons \text{H}_2\text{NO}_3^+ + \text{HSO}_4^-

    Protonated nitric acid

    Step II:

    H2NO3+⟶NO2++H2O\text{H}_2\text{NO}_3^+ \longrightarrow \text{NO}_2^+ + \text{H}_2\text{O}

    Nitronium ion

    In this process, sulphuric acid acts as an acid (proton donor) and nitric acid acts as a base (proton acceptor).

Step (b): Formation of Carbocation (Arenium Ion)

The electrophile (E+\text{E}^+) attacks the electron-rich benzene ring. This results in the formation of a σ\sigma-complex, also called an arenium ion. In this intermediate, one of the carbon atoms (the one attacked by the electrophile) becomes sp3\text{sp}^3 hybridised.

The arenium ion is not stable, but it is stabilised by resonance. The positive charge is delocalised over three carbon atoms of the ring (the ortho and para positions relative to the point of attack).

Important

Loss of aromaticity

The sigma complex (arenium ion) loses its aromatic character because the delocalisation of π\pi electrons is interrupted at the sp3\text{sp}^3 hybridised carbon. The ring is no longer a fully conjugated, planar system.

Diagram arenium-ion-sigma-complex-9.5.5-mechanismFormation of the sigma complex (arenium ion): the electrophile E+ attacks the electron-rich benzene ring, and the carbon under attack becomes sp3 hybridised, carrying both its hydrogen and the electrophile while the ring keeps a delocalised positive charge.
Fig. arenium-ion-sigma-complex-9.5.5-mechanism — Formation of the sigma complex (arenium ion): the electrophile E+ attacks the electron-rich benzene ring, and the carbon under attack becomes sp3 hybridised, carrying both its hydrogen and the electrophile while the ring keeps a delocalised positive charge.

Mechanism step (b): the electrophile E+E^+ attacks benzene's electron-rich π\pi cloud (curved arrow), forming the sigma complex (arenium ion). The attacked carbon becomes sp3sp^3 hybridised, carrying both its hydrogen and the electrophile, while the remaining positive charge is spread over the rest of the ring — whose aro …

Diagram arenium-ion-resonance-stabilization-9.5.5-mechanismResonance stabilisation of the arenium ion: the positive charge is delocalised over the two ortho carbons and the para carbon (three contributing structures), so the sigma complex is written as a hybrid with a dashed circle over five ring carbons.
Fig. arenium-ion-resonance-stabilization-9.5.5-mechanism — Resonance stabilisation of the arenium ion: the positive charge is delocalised over the two ortho carbons and the para carbon (three contributing structures), so the sigma complex is written as a hybrid with a dashed circle over five ring carbons.

Why the unstable arenium ion survives long enough to react on: its positive charge is delocalised by resonance over the two ortho carbons and the para carbon (the three contributing structures shown, linked by curved electron-pushing arrows), equivalent to the hybrid dr …

Step (c): Removal of Proton

To restore the stable aromatic character of the ring, the σ\sigma-complex releases a proton (H+\text{H}^+) from the sp3\text{sp}^3 hybridised carbon. This proton is removed by the counter-ion present in the reaction mixture.

  • In the case of halogenation, alkylation, and acylation, the proton is removed by [AlCl4]−[\text{AlCl}_4]^-.
  • In the case of nitration, the proton is removed by [HSO4]−[\text{HSO}_4]^-.

The removal of the proton regenerates the aromatic ring and gives the final substituted product.

Diagram removal-of-proton-mechanism-9.5.5-mechanismRemoval of proton: to restore aromaticity the sigma complex loses H+ from its sp3 hybridised carbon, taken by [AlCl4]- (halogenation, alkylation, acylation) or by [HSO4]- (nitration), leaving the substituted benzene product.
Fig. removal-of-proton-mechanism-9.5.5-mechanism — Removal of proton: to restore aromaticity the sigma complex loses H+ from its sp3 hybridised carbon, taken by [AlCl4]- (halogenation, alkylation, acylation) or by [HSO4]- (nitration), leaving the substituted benzene product.

Mechanism step (c): to regain aromatic stability the sigma complex releases a proton from its sp3sp^3 carbon. The proton is carried off by [AlClX4]X−\ce{[AlCl4]^-} (in halogenation, alkylation and acylation) or by [HSOX4]X−\ce{[HSO4]^-} (in nitration), restoring the fully de …

Addition Reactions

Under normal conditions, benzene does not undergo addition reactions because it would lose its aromatic stability. However, under vigorous conditions, addition is possible.

Hydrogenation: At high temperature and/or pressure, in the presence of a nickel catalyst, benzene adds three molecules of hydrogen to give cyclohexane.

C6H6+3H2→Ni, Δ, pressureC6H12\text{C}_6\text{H}_6 + 3\text{H}_2 \xrightarrow{\text{Ni, } \Delta, \text{ pressure}} \text{C}_6\text{H}_{12}

Cyclohexane

Diagram eq-9.80-benzene-hydrogenation-cyclohexane-9.5.5-additionAddition of hydrogen to benzene: under vigorous conditions with a nickel catalyst, benzene adds three molecules of H2 to give cyclohexane, a fully saturated ring (equation 9.80).
Fig. eq-9.80-benzene-hydrogenation-cyclohexane-9.5.5-addition — Addition of hydrogen to benzene: under vigorous conditions with a nickel catalyst, benzene adds three molecules of H2 to give cyclohexane, a fully saturated ring (equation 9.80).

Equation 9.80 — addition forced under vigorous conditions: with a nickel catalyst and heating, benzene adds three molecules of hydrogen to give cyclohexane, a fully saturated ring. The aromatic system is destroyed, which is exac …

Halogenation (Addition): Under ultraviolet light, three molecules of chlorine add to benzene to produce benzene hexachloride (C6H6Cl6\text{C}_6\text{H}_6\text{Cl}_6), also known as gammaxane or BHC (benzene hexachloride). This is an insecticide.

C6H6+3Cl2→UV lightC6H6Cl6\text{C}_6\text{H}_6 + 3\text{Cl}_2 \xrightarrow{\text{UV light}} \text{C}_6\text{H}_6\text{Cl}_6

Benzene hexachloride (BHC)

Diagram eq-9.81-benzene-hexachloride-bhc-9.5.5-additionAddition of chlorine to benzene under ultraviolet light at 500 K: three Cl2 molecules add across the ring, giving benzene hexachloride C6H6Cl6 (BHC, gammaxane), drawn as the saturated ring with one Cl on every carbon (equation 9.81).
Fig. eq-9.81-benzene-hexachloride-bhc-9.5.5-addition — Addition of chlorine to benzene under ultraviolet light at 500 K: three Cl2 molecules add across the ring, giving benzene hexachloride C6H6Cl6 (BHC, gammaxane), drawn as the saturated ring with one Cl on every carbon (equation 9.81).

Equation 9.81 — photochemical addition: under ultraviolet light at 500 K, three chlorine molecules add across the ring to give benzene hexachloride, CX6HX6ClX6\ce{C6H6Cl6} (BHC, gammaxane) — drawn, as in the textbook, as the saturated ring with one Cl on every carbon. This radical addition needs no L …

Combustion (Oxidation)

When heated in air (or oxygen), benzene burns with a sooty flame, producing carbon dioxide and water.

2C6H6+15O2⟶12CO2+6H2O2\text{C}_6\text{H}_6 + 15\text{O}_2 \longrightarrow 12\text{CO}_2 + 6\text{H}_2\text{O}

The general combustion reaction for any hydrocarbon (CxHy\text{C}_x\text{H}_y) can be written as:

CxHy+(x+y4)O2⟶xCO2+y2H2O\text{C}_x\text{H}_y + \left(x + \frac{y}{4}\right) \text{O}_2 \longrightarrow x\text{CO}_2 + \frac{y}{2} \text{H}_2\text{O}

Directive Influence of a Functional Group in Monosubstituted Benzene

When a monosubstituted benzene (benzene with one group already attached) is subjected to further substitution, the three possible disubstituted products (ortho, meta, and para) are not formed in equal amounts. Two distinct types of behaviour are observed:

  1. The incoming group goes predominantly to the ortho and para positions.
  2. The incoming group goes predominantly to the meta position.

This behaviour depends entirely on the nature of the substituent already present on the ring. It does not depend on the nature of the entering group. This is known as the directive influence of substituents.

Ortho and Para Directing Groups

Groups that direct the incoming group to the ortho and para positions are called ortho and para directing groups.

›Proof

Example: The directive influence of the −OH-\text{OH} group (Phenol)

Phenol is a resonance hybrid of the following structures:

C6H5OH⟷Structures showing negative charge on ortho and para carbons\text{C}_6\text{H}_5\text{OH} \longleftrightarrow \text{Structures showing negative charge on ortho and para carbons}

It is clear from these resonating structures that the electron density is more on the ortho and para positions. Therefore, substitution by an electrophile takes place mainly at these positions.

…