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Chemistry · Ch 6 — States of Matter

Dalton's Law of Partial Pressures

6.6.2

Dalton's Law of Partial Pressures

Total pressure of a gas mixture

John Dalton formulated this law in 1801: the total pressure exerted by a mixture of non-reacting gases equals the sum of the partial pressures of the individual gases — where the partial pressure of a gas in a mixture is the pressure that gas alone would exert if it occupied the same volume, at the same temperature, by itself.

pTotal=p1+p2+p3+⋯(at constant T, V)p_{\text{Total}} = p_{1}+p_{2}+p_{3}+\cdots\qquad(\text{at constant }T,\ V)

Correcting for water vapour

Gases collected over water pick up water vapour and become moist. The pressure exerted by this saturated water vapour is called aqueous tension, and it must be subtracted to get the pressure of the dry gas:

pDry gas=pTotal−Aqueous tensionp_{\text{Dry gas}} = p_{\text{Total}} - \text{Aqueous tension}

Table 5.3 lists aqueous tension at various temperatures:

Temp./KPressure/barTemp./KPressure/bar
273.150.0060295.150.0260
283.150.0121297.150.0295
288.150.0168299.150.0331
291.150.0204301.150.0372
293.150.0230303.150.0418

Partial pressure in terms of mole fraction

For three gases with n1n_1, n2n_2, n3n_3 moles sharing volume VV at temperature TT, each contributes pi=niRTVp_i = \dfrac{n_iRT}{V}, so:

pTotal=p1+p2+p3=(n1+n2+n3)RTVp_{\text{Total}} = p_{1}+p_{2}+p_{3} = (n_{1}+n_{2}+n_{3})\frac{RT}{V}

Dividing p1p_1 by pTotalp_\text{Total}, the RT/VRT/V terms cancel, leaving:

p1pTotal=n1n1+n2+n3=n1n=x1\frac{p_{1}}{p_{\text{Total}}} = \frac{n_{1}}{n_{1}+n_{2}+n_{3}} = \frac{n_{1}}{n} = x_{1} …

Table 5.3Aqueous Tension of Water (Vapour Pressure) as a Function of Temperature
Temp./KPressure/barTemp./KPressure/bar
273.150.0060295.150.0260
283.150.0121297.150.0295
288.150.0168299.150.0331