Skip to content
Question of 72

Q.The distance between the points (2,3,5)(2, 3, 5) and (4,3,1)(4, 3, 1) is

(a) 252\sqrt{5}
(b) 353\sqrt{5}
(c) 525\sqrt{2}
(d) none of these
Jharkhand JacJAC Intermediate Board (1st Year) 2023MCQ· 1mImportance★★★★★
0% · 0/72 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Applying the 3D distance formula between (2,3,5)(2,3,5) and (4,3,1)(4,3,1) gives 252\sqrt5.

The distance between two points (x1,y1,z1)(x_1,y_1,z_1) and (x2,y2,z2)(x_2,y_2,z_2) in space is:

d=(x2−x1)2+(y2−y1)2+(z2−z1)2d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.