Skip to content
Question of 72

Q.Find the distance of the point (2,3,5)(2, 3, 5) from the origin.

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2026Subjective· 2mImportance★★★★★
0% · 0/72 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The distance is 38\sqrt{38} units.

The distance of a point (x,y,z)(x,y,z) from the origin (0,0,0)(0,0,0) is given by:

d=x2+y2+z2d = \sqrt{x^2+y^2+z^2}

For the point (2,3,5)(2,3,5):

d=22+32+52=4+9+25=38d = \sqrt{2^2+3^2+5^2} = \sqrt{4+9+25} = \sqrt{38}

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.