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Q.If the angles of a triangle are in the ratio 3:4:53:4:5, the smallest angle in radian will be

(a) π4\dfrac{\pi}{4}
(b) π3\dfrac{\pi}{3}
(c) π2\dfrac{\pi}{2}
(d) 5π12\dfrac{5\pi}{12}
Jharkhand JacJAC Intermediate Board (1st Year) 2022MCQ· 1mImportance★★★★★
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Split 180°180° into 3:4:53:4:5 parts, then convert the smallest share to radians.

Sum of ratio parts =3+4+5=12=3+4+5=12, so each part =180°12=15°=\dfrac{180°}{12}=15°. The angles are 3×15°=45°3\times15°=45°, 4×15°=60°4\times15°=60°, 5×15°=75°5\times15°=75°. The smalles …

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