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Q.The angles of a triangle are in the ratio 1:3:51:3:5. The smallest in radian will be

(a) π9\dfrac{\pi}{9}
(b) π3\dfrac{\pi}{3}
(c) 5π9\dfrac{5\pi}{9}
(d) None of these
Jharkhand JacJAC Intermediate Board (1st Year) 2024MCQ· 1mImportance★★★★★
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Use the angle-sum property of a triangle to find each angle from the given ratio, then convert the smallest to radians.

Let the angles be x,3x,5xx, 3x, 5x (in the ratio 1:3:51:3:5). The angles of a triangle sum to 180∘180^\circ:

x+3x+5x=180∘  ⟹  9x=180∘  ⟹  x=20∘x + 3x + 5x = 180^\circ \implies 9x = 180^\circ \implies x = 20^\circ

So the angles are 20∘,60∘,100∘20^\circ, 60^\circ, 100^\circ. The smallest is 20∘20^\circ.

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