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Physics · Ch 6 — Electromagnetic Induction

Self-inductance

6.7.2

Self-inductance

What is Self-Inductance?

Self-inductance is the phenomenon where a changing current in a coil induces an emf in the same coil. This happens because the current produces a magnetic flux through the coil; when the current changes, the flux changes, and by Faraday’s law, an emf is induced. This induced emf always opposes the change in current (Lenz’s law) and is called the back emf.

Flux and Self-Inductance

For a coil with NN turns, the total flux linkage NΦBN \Phi_B is proportional to the current II flowing through it:

NΦB=LIN \Phi_B = L I

Here:

  • NΦBN \Phi_B is the total magnetic flux linkage (in weber-turns).
  • II is the current (in amperes).
  • LL is the self-inductance (or coefficient of self-induction) of the coil, measured in henry (H).

Induced emf from Self-Inductance

Using Faraday’s law, the induced emf ε\varepsilon is:

ε=−ddt(NΦB)=−LdIdt\varepsilon = -\frac{d}{dt}(N \Phi_B) = -L \frac{dI}{dt}

The negative sign indicates that the self-induced emf opposes the change in current (increase or decrease). This is the back emf.

Self-Inductance of a Long Solenoid

Consider a long solenoid of:

  • Cross-sectional area AA
  • Length ll
  • Number of turns per unit length nn

The magnetic field inside (neglecting edge effects) is:

B=μ0nIB = \mu_0 n I

The total flux linkage for nlnl turns is:

NΦB=(nl)(BA)=(nl)(μ0nIA)=μ0n2IAlN \Phi_B = (nl)(B A) = (nl)(\mu_0 n I A) = \mu_0 n^2 I A l

Thus, the self-inductance LL is:

L=NΦBI=μ0n2AlL = \frac{N \Phi_B}{I} = \mu_0 n^2 A l

If the solenoid is filled with a material of relative permeability μr\mu_r, then:

L=μ0μrn2AlL = \mu_0 \mu_r n^2 A l

Key point: LL depends only on the geometry (size, shape, number of turns) and the magnetic properties of the medium inside the coil.

Energy Stored in an Inductor

Work must be done against the back emf to establish a current. The rate of work is:

dWdt=εI=LIdIdt\frac{dW}{dt} = \varepsilon I = L I \frac{dI}{dt}

Integrating from 00 to II gives the total energy stored as magnetic potential energy:

W=∫0ILI dI=12LI2W = \int_0^I L I \, dI = \frac{1}{2} L I^2

This is analogous to kinetic energy 12mv2\frac{1}{2} m v^2 — LL acts like electrical inertia, opposing changes in current.

Magnetic Energy Density

For a solenoid, using L=μ0n2AlL = \mu_0 n^2 A l and B=μ0nIB = \mu_0 n I, the energy stored is:

UB=12LI2=12B2μ0(Al)U_B = \frac{1}{2} L I^2 = \frac{1}{2} \frac{B^2}{\mu_0} (A l)

The volume containing the field is V=AlV = A l, so the magnetic energy density is:

uB=UBV=B22μ0u_B = \frac{U_B}{V} = \frac{B^2}{2 \mu_0} …