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Q.Show that pH + pOH = 14 at 298K.

Karnataka PUCKarnataka School Examination and Assessment Board (1st PUC) 2026Subjective· 3mImportance★★★★★
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[!TLDR]

Kw = [H+][OH-] = 10^-14 at 298K. Taking -log of both sides: -log[H+] + (-log[OH-]) = -log(10^-14), i.e. pH + pOH = 14.

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