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Miscellaneous Exercise · Q4

Q.−15<3(x−2)5≤0-15 < \dfrac{3(x - 2)}{5} \le 0

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Multiply all three parts by 55, distribute, add 66, and divide by 33. The solution is −23<x≤2-23 < x \le 2, i.e. (−23,2](-23, 2].

A compound inequality is solved by operating on all three parts at once. Every multiplier here is positive, so the inequality signs never flip.

Step-by-step solution

  1. Clear the denominator. Multiply every part by 55:

−15⋅5<3(x−2)≤0⋅5-15\cdot 5 < 3(x-2) \le 0\cdot 5

−75<3(x−2)≤0-75 < 3(x-2) \le 0

  1. Distribute the 33.

−75<3x−6≤0-75 < 3x - 6 \le 0

  1. Isolate the xx-term. Add 66 to all three parts:

−69<3x≤6-69 < 3x \le 6

  1. Solve for xx. Divide every part by 33: −23<x≤2-23 < x \le 2 …

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