Q.Which of the following enzymes catalyse the removal of nucleotides from the ends of DNA?
Concept understanding — Restriction Enzyme Action
Imagine you have a long, tangled piece of string, and you need to cut it into smaller, specific pieces — not just anywhere, but exactly at the places where a certain pattern of letters appears. That is the core idea behind restriction enzyme action.
In the world of biology, the "string" is a DNA molecule — the long, thread-like chemical that carries the genetic instructions for every living thing. A restriction enzyme is a molecular "scissors" that cuts DNA, but it is incredibly precise. It does not chop randomly. Instead, it recognises a very specific, short sequence of DNA letters (usually 4 to 8 base pairs long) and cuts only at that exact spot.
Think of it like a word processor's "Find and Replace" function, but instead of replacing text, the enzyme finds a specific word and cuts the page at that word.
This ability to cut DNA at precise locations is what makes restriction enzymes the fundamental tool of genetic engineering. Without them, scientists would have no way to isolate a specific gene from a long DNA strand.
How does the enzyme "know" where to cut?
The DNA molecule is made of two strands twisted together (the famous double helix). Each strand has a sequence of four chemical "letters": A, T, G, and C. A restriction enzyme scans along the DNA until it finds its target sequence — a short, palindromic pattern (meaning it reads the same forwards on one strand and backwards on the other). For example, the enzyme EcoRI recognises the sequence GAATTC.
When it finds this exact sequence, it binds to the DNA and makes a cut in both strands. The cut can be one of two types:
- Sticky ends: The enzyme cuts the two DNA strands at different points, leaving short, single-stranded overhangs. These overhangs are like pieces of Velcro — they can easily stick to a complementary overhang from another DNA piece cut by the same enzyme. This is extremely useful for joining different DNA fragments together.
- Blunt ends: The enzyme cuts both strands straight across at the same point, leaving no overhang. These are harder to join together later, but they are still useful.
Why does this matter?
Restriction enzymes are the reason we can manipulate DNA at all. They allow scientists to:
- Cut out a specific gene from the DNA of one organism (say, the human insulin gene).
- Cut open a carrier DNA (like a plasmid from a bacterium) at the same spot.
- Insert the gene into the carrier, because the sticky ends match perfectly.
- Splice the carrier back together using another enzyme (DNA ligase), creating a recombinant DNA molecule.
This is the foundation of modern biotechnology — from producing human insulin in bacteria to creating genetically modified crops and developing gene therapies.
The key takeaway from the NCERT textbook is that restriction enzymes are molecular scissors that cut DNA at specific recognition sites. Their action produces fragments with either sticky ends or blunt ends, and this precise cutting is what makes genetic engineering possible. The enzyme itself is a protein, and it is named after the bacterium from which it is isolated (e.g., EcoRI from Escherichia coli).
In short: Restriction enzyme action is the controlled, precise cutting of DNA at predetermined locations — the first and most essential step in any DNA manipulation experiment.
Restriction enzyme action is one of the most tested mechanisms in the NCERT Class 12 Biology chapter on Biotechnology: Principles and Processes, and appears in searches like "restriction enzymes class 12 biology sticky ends" or "EcoRI recognition site important questions." This is a near-certain topic in both CBSE board papers and NEET's biotechnology section every year.
Nucleases are enzymes that cleave the phosphodiester bonds of nucleic acids. They are broadly classified based on their site of action on the DNA molecule.
- Exonucleases remove nucleotides one at a time from the ends of a DNA strand. They act on the terminal phosphodiester bonds.
- Endonucleases make cuts at specific positions within the DNA molecule, not at the ends. Restriction endonucleases, like Hind-II, are a type of endonuclease that recognize specific sequences and cut within them.
- DNA ligase, on the other hand, is involved in joining DNA fragments by forming phosphodiester bonds, not removing nucleotides.
Therefore, the enzyme that catalyses the removal of nucleotides from the ends of DNA is an exonuclease.
The enzyme that catalyses the removal of nucleotides from the ends of DNA is (B) exonuclease.
Exonucleases are the enzymes responsible for removing nucleotides sequentially from the ends of a DNA strand.
Understanding how DNA is manipulated in molecular biology often begins with the action of enzymes that can cut or modify the DNA molecule. Among these, restriction enzymes play a pivotal role, acting like molecular scissors that recognise and cut DNA at specific sites. These enzymes are broadly categorised based on how they interact with the DNA strand.
Restriction enzymes are a class of nucleases, which are enzymes that cleave the phosphodiester bonds between nucleotide subunits of nucleic acids. These nucleases can be further divided into two main types based on their mode of action: endonucleases and exonucleases.
Endonucleases are enzymes that make cuts within the DNA strand. They do not remove nucleotides from the ends but rather cleave the internal phosphodiester bonds at specific recognition sequences. For instance, the enzyme Hind-II, which was the first restriction endonuclease isolated, always cuts DNA molecules at a particular point after recognising a specific sequence of six base pairs. This precise internal cutting is crucial for genetic engineering, as it allows scientists to generate specific DNA fragments.
Exonucleases, on the other hand, are enzymes that catalyse the removal of nucleotides from the ends of a DNA strand. They work sequentially, detaching one nucleotide at a time from either the 5' or 3' end of the DNA molecule. Their action is like trimming the edges of a piece of string, rather than cutting it in the middle. This property makes exonucleases important in processes like DNA repair and degradation.
The fundamental distinction lies in their cutting location: endonucleases cut within the DNA, while exonucleases remove nucleotides from the ends.
Let's consider the other options provided:
- DNA ligase is an enzyme with a function entirely different from cutting or removing nucleotides. Its role is to join DNA fragments together by forming phosphodiester bonds between them. It acts as a "molecular glue," essential for sealing nicks in the DNA backbone and for joining desired DNA fragments in recombinant DNA technology.
- Hind-II is a specific example of a restriction endonuclease. As discussed, it cuts DNA internally at a specific recognition sequence, rather than removing nucleotides from the ends.
Therefore, the enzyme that specifically catalyses the removal of nucleotides from the ends of DNA is an exonuclease.
The enzyme that catalyses the removal of nucleotides from the ends of DNA is (B) exonuclease.
Alternative Approach: A "Rope" Analogy for Cut-Site Location
Endonuclease vs exonuclease is easy to confuse in the moment of an exam; anchoring both
terms to a simple physical analogy removes the ambiguity instantly.
Step 1: Picture a length of rope representing a DNA strand.
An endonuclease is like cutting the rope somewhere in the middle -- "endo-" means
"within". It needs no free end to act, and can even cut a circular strand (which has no
ends at all).
Step 2: An exonuclease is like unravelling the rope from one of its ends inward.
"Exo-" means "outside/from the edge". It removes one nucleotide at a time, working
progressively inward from a free 5' or 3' terminus -- it cannot start in the middle of
an intact strand.
Step 3: Test the four options against this picture.
- Endonuclease -- cuts within the strand, not from an end. Eliminate.
- Exonuclease -- removes nucleotides one at a time starting from an end. Matches the question exactly.
- DNA ligase -- joins fragments together (the opposite operation entirely, not a cutting enzyme at all). Eliminate.
- Hind-II -- a specific example of a restriction endonuclease, so it also cuts within the strand at its recognition site, not from an end. Eliminate. Key Takeaway: The "rope" analogy (cutting in the middle vs unravelling from an end) is a durable way to remember which nuclease type needs a free terminus to act and which does not -- useful well beyond this one question, e.g. for understanding DNA repair and proofreading mechanisms too.
- KCET 2026Set UNKNOWN1 markMCQQ.Given below are two statements. Statement I: Restriction enzyme BamHI has its recognition site in tetR region of pBR322. Statement II: E.coli having pBR322 with a desired DNA if inserted at BamHI site can grow in medium containing tetracycline. In the light of the above statements, choose the correct answer from the options given below. (A) Both Statement I and Statement II are true (B) Both Statement I and Statement II are false (C) Statement I is true, but Statement II is false (D) Statement I is false, but Statement II is true
›Reveal solutionSolution
pBR322 carries unique restriction sites within its two antibiotic-resistance genes; inserting DNA at one of these sites inactivates that gene rather than preserving resistance.
Step 1 — Checking Statement I
The cloning vector pBR322 has two antibiotic resistance genes, ampicillin resistance (ampR) and tetracycline resistance (tetR), each containing unique restriction sites usable for cloning. The BamHI site (along with SalI) lies within the tetR gene (PstI lies within ampR). So Statement I is true.
Step 2 — Checking Statement II
When foreign DNA is inserted at a restriction site located inside the tetR gene, it disrupts the gene's coding sequence — this is called insertional inactivation. As a result, a recombinant E. coli carrying an insert at the BamHI site loses tetracycline resistance and therefore cannot grow in a medium containing tetracycline (such colonies are identified by replica plating as tetracycline-sensitive). So Statement II, which claims it can grow, is false.
✓Final answerThe correct option is (C) — Statement I is true, but Statement II is false.
- KCET 2026Set UNKNOWN1 markMCQQ.Match List I with List II List Ia) Visualization of DNA in gel electrophoresisb) Precipitation of DNAc) Breaking of cell wall of bacteriad) Breaking of cell wall of fungus List IIi) Chitinaseii) Lysozymeiii) Chilled ethanoliv) Ethidium bromide Codes: (A) a - iv, b - iii, c - ii, d - i (B) a - iii, b - i, c - i, d - ii (C) a - iv, b - i, c - ii, d - iii (D) a - iii, b - ii, c - iv, d - i
›Reveal solutionSolution
Matching each rDNA-technology step to its reagent: visualisation → ethidium bromide, DNA precipitation → chilled ethanol, bacterial cell wall lysis → lysozyme, fungal cell wall lysis → chitinase, giving a-iv, b-iii, c-ii, d-i.
Step 1 — (a) Visualisation of DNA in gel electrophoresis
DNA fragments separated by gel electrophoresis are stained with ethidium bromide and viewed under UV light as bright orange-coloured bands. So a → iv.
Step 2 — (b) Precipitation of DNA
After isolating DNA in aqueous form, it is precipitated out of solution by adding chilled ethanol. So b → iii.
Step 3 — (c) Breaking the cell wall of bacteria
Bacterial cell walls (made largely of peptidoglycan) are digested using the enzyme lysozyme. So c → ii.
Step 4 — (d) Breaking the cell wall of fungus
Fungal cell walls (made of chitin) are digested using the enzyme chitinase. So d → i.
Step 5 — Assembling the code
Combining these: a-iv, b-iii, c-ii, d-i, which corresponds to option (A).
✓Final answerThe correct option is (A) — a - iv, b - iii, c - ii, d - i.
- KCET 2023Set B-41 markMCQQ.The toxic substance 'haemozoin' responsible for high fever and chill, is released in which of the following diseases? (A) Typhoid (B) Dengue (C) Pneumonia (D) Malaria
›Reveal solutionSolution
Haemozoin is the toxic pigment liberated when Plasmodium-infected RBCs burst — the direct cause of malaria's periodic chill-and-fever.
Step 1 — The malarial life cycle in the human host
- An infected female Anopheles mosquito injects sporozoites while biting.
- The parasites first multiply in the liver cells.
- They then attack the red blood cells (RBCs), multiplying inside them.
- The RBCs rupture, releasing new parasites and a toxic substance called haemozoin.
Step 2 — Why haemozoin causes the fever
Haemozoin is a waste product formed as Plasmodium digests the haemoglobin of the RBC (it polymerises the toxic free haem it cannot excrete). When the RBCs burst synchronously, a bolus of haemozoin enters the circulation and triggers the immune/inflammatory response responsible for the chill and high fever recurring every three to four days.
Step 3 — Complete the cycle
When another mosquito bites the infected person, the gametocytes it takes up develop and fuse in the mosquito's gut, forming sporozoites that migrate to its salivary glands — so the mosquito is the vector, and the parasite is a digenic organism (needing two hosts).
Step 4 — Eliminate the other options
- (A) Typhoid — Salmonella typhi, a bacterium; sustained high fever, but no haemozoin (it is not an RBC parasite).
- (B) Dengue — a virus spread by Aedes; no haemozoin.
- (C) Pneumonia — Streptococcus pneumoniae / Haemophilus influenzae, a lung infection. (Note the trap: Haemophilus merely sounds like haemozoin.)
✓Final answerThe correct option is (D) Malaria — haemozoin is released when Plasmodium-infected RBCs rupture.
ANSWER: D
- KCET 2021Set C-31 markMCQQ.Match the following Column-I i. Cyclosporin-A ii. Streptokinase iii. Statins iv. Penicillin Column-II a. Clot busters b. Antibiotic c. Immuno suppressive agent d. Blood cholesterol lowering agent (A) i-c, ii-a, iii-d, iv-b (B) i-c, ii-d, iii-a, iv-b (C) i-a, ii-b, iii-c, iv-d (D) i-a, ii-b, iii-d, iv-c
›Reveal solutionSolution
This question tests your recall of the specific medical applications of four well-known microbial products. The correct match is Cyclosporin-A (immunosuppressive), Streptokinase (clot buster), Statins (cholesterol-lowering), and Penicillin (antibiotic), which corresponds to option (A).
The key here is not to memorise blindly, but to connect each drug to its biological function and the disease or condition it treats. Each of these is a product of microbial fermentation or extraction, and their names often hint at their use.
Let’s go through each one.
-
Cyclosporin-A (i)
This is a cyclic peptide produced by the fungus Trichoderma polysporum. Its primary medical use is as an immunosuppressive agent — it suppresses the immune system to prevent rejection of transplanted organs. So it matches with c.
-
Streptokinase (ii)
Produced by the bacterium Streptococcus, this enzyme dissolves blood clots by converting plasminogen into plasmin. It is used in emergency medicine to treat heart attacks and strokes — it is a clot buster. So it matches with a.
-
Statins (iii)
These are produced by the fungus Monascus purpureus (and also synthesised chemically). They work by inhibiting the enzyme HMG-CoA reductase, which is key in cholesterol synthesis. Their effect is to lower blood cholesterol levels. So they match with d.
-
Penicillin (iv)
The classic antibiotic discovered by Alexander Fleming from the mould Penicillium notatum. It kills bacteria by interfering with cell wall synthesis. It is an antibiotic. So it matches with b.
Watch outA common mistake is to confuse Streptokinase (a clot buster) with Statins (cholesterol-lowering). Remember: "kinase" often means an enzyme that acts on proteins — here it dissolves clots. Statins end with "-statin", which hints at "static" or "stopping" cholesterol.
Now, putting the matches together:
i → c, ii → a, iii → d, iv → b.
✓Final answerThe correct option is (A) i-c, ii-a, iii-d, iv-b.
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- KCET 2021Set C-31 markMCQQ.α-1 antitrypsin is (A) an antacid (B) an enzyme (C) used to treat emphysema (D) used to treat arthritis
›Reveal solutionSolution
α-1 antitrypsin is a protease inhibitor that protects lung tissue from damage; its deficiency causes emphysema, and the purified protein is used as a therapy for emphysema. The correct option is (C).
The concept: What is α-1 antitrypsin, and why does it matter?
α-1 antitrypsin (AAT) is a serine protease inhibitor — a protein made primarily in the liver and secreted into the bloodstream. Its main job is to neutralize neutrophil elastase, an enzyme released by white blood cells during inflammation. If left unchecked, neutrophil elastase chews up the elastic fibres in lung tissue, leading to emphysema (a form of chronic obstructive pulmonary disease, COPD).
So AAT is not an enzyme itself — it inhibits an enzyme. It is also not an antacid (that neutralizes stomach acid), and it has no role in arthritis treatment. The key clinical link: people born with a genetic deficiency of AAT are at high risk of early-onset emphysema. The therapy? Purified AAT from human plasma is infused intravenously to raise blood levels and protect the lungs.
Step-by-step reasoning
-
Eliminate (A) — an antacid
Antacids are simple bases like magnesium hydroxide or calcium carbonate that neutralize stomach acid. α-1 antitrypsin is a protein, not a base, and has nothing to do with gastric pH. So (A) is wrong.
-
Eliminate (B) — an enzyme
AAT is a protease inhibitor, not a protease. It binds to and inactivates the enzyme neutrophil elastase. Calling it an enzyme would be like calling a lock a key — it blocks the action, not catalyses a reaction. So (B) is wrong.
-
Consider (D) — used to treat arthritis
Arthritis (especially rheumatoid arthritis) involves inflammation, but AAT therapy is not a standard treatment for it. Some research has explored AAT for other inflammatory conditions, but the established, approved use is for emphysema due to AAT deficiency. So (D) is not correct in the exam context.
-
Confirm (C) — used to treat emphysema
This is the direct application. Patients with AAT deficiency receive weekly intravenous infusions of purified AAT (brand name: Prolastin, among others). This slows the progression of emphysema and reduces lung damage. The therapy is specifically indicated for emphysema caused by AAT deficiency.
Watch outA common mistake is to think α-1 antitrypsin is an enzyme because its name ends in "-in" (like trypsin, which is an enzyme). But the "anti-" prefix is the clue: it opposes trypsin-like enzymes. Always check function, not just name.
TipIn molecular biology, many proteins with "-in" endings are inhibitors (e.g., α-1 antitrypsin, antithrombin). The suffix alone doesn't tell you whether it's an enzyme or an inhibitor — you need to know what it does.
✓Final answerThe correct option is (C): α-1 antitrypsin is used to treat emphysema.
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- KCET 2019Set A-11 markMCQQ.In cloning vectors, antibiotic resistant genes are helpful for (A) Selection of recombinants (B) Cleaving of vector by REN (C) Transfer of foreign gene to the host (D) Making the host cells competent
›Reveal solutionSolution
Antibiotic-resistance genes act as selectable markers, letting us pick out the few transformed/recombinant cells from a huge background of untransformed ones.
Step 1 — The problem a selectable marker solves.
Transformation is very inefficient: only a tiny fraction of the host cells actually take up the plasmid. We need a way to make only those cells grow.
Step 2 — How the resistance gene does it.
The vector carries, say, ampR (ampicillin resistance). Plating the transformation mixture on ampicillin-containing medium kills every cell that did not take up the vector; survivors necessarily carry it. This is selection.
Step 3 — Selecting recombinants specifically.
pBR322 carries two markers, ampR and tetR. A foreign gene ligated into the tetR site inactivates it (insertional inactivation). So:
- grows on ampicillin and tetracycline ⇒ non-recombinant (vector re-circularised),
- grows on ampicillin but not tetracycline ⇒ recombinant.
Step 4 — Reject the others.
- (B) Cleaving of the vector is done by restriction endonucleases, a property of the enzyme, not of a marker gene.
- (C) Transfer of the foreign gene into the host is achieved by the vector's ori + transformation/vector machinery, not by the resistance gene.
- (D) Competence is induced by divalent cations such as CaCl2 (or heat shock), again nothing to do with the marker.
✓Final answerThe correct option is (A) — Selection of recombinants.
ANSWER: A
- KCET 2018Set A-11 markMCQQ.The technique of bombarding plant cells with high velocity microparticles of gold or tungsten, coated with DNA, is (A) Microinjection (B) Biolistic method (C) Heat shock method (D) By disarmed pathogen vector
›Reveal solutionSolution
"Bombarding with high-velocity DNA-coated gold/tungsten microparticles" is the textbook definition of the biolistic (gene gun) method of direct gene transfer.
Step 1 — The problem the method solves.
Plant cells have a rigid cellulose cell wall, so naked DNA cannot simply diffuse in. Direct gene-transfer methods must physically breach the wall and membrane. The biolistic method does exactly that: DNA is precipitated onto inert, dense microparticles of gold or tungsten, which are then accelerated to high velocity by a gene gun so they pierce the cell wall and deliver the DNA into the cell/nucleus.
Step 2 — Why the other three are not this method.
- (A) Microinjection — DNA is injected directly into the nucleus with a fine glass micro-needle; used for animal cells (e.g. producing transgenic animals). No particles, no bombardment.
- (C) Heat-shock method — competent bacterial cells held in divalent Ca²⁺ are given a brief 42 °C shock so plasmid DNA passes through transient pores. Chemical/thermal, not mechanical.
- (D) Disarmed pathogen vector — Agrobacterium tumefaciens, the "natural genetic engineer of plants", whose Ti-plasmid is disarmed (tumour genes removed) and used to carry the gene in. This is vector-mediated, not particle bombardment.
Step 3 — Commit.
Only the biolistic/gene-gun method matches every element of the stem (high velocity + gold/tungsten microparticles + DNA coating + plant cells).
✓Final answerThe correct option is (B) — Biolistic method.
ANSWER: B
- KCET 2018Set A-11 markMCQQ.Choose the bacterium which is not a source of REN: (A) \textit{Haemophilus influenzae} (B) \textit{Escherichia coli} (C) \textit{Agrobacterium tumefaciens} (D) \textit{Bacillus amyloliquefaciens}
›Reveal solutionSolution
Read the restriction-enzyme naming convention: the first letter is the genus, the next two the species — Eco, Hin, Bam all trace back to bacteria in this list; Agrobacterium does not name any RE, it supplies the Ti-plasmid vector.
Step 1 — What REN means and how REs are named.
A restriction endonuclease cuts DNA at a specific palindromic recognition sequence. Its name is built from its bacterial source: first letter = genus (capital), next two letters = species, then the strain and a Roman numeral for the order of isolation.
Step 2 — Test each option.
- (A) Haemophilus influenzae → HindII (the first restriction endonuclease ever isolated) and HindIII. A source. ✓
- (B) Escherichia coli → EcoRI, the workhorse enzyme cutting 5′-G↓AATTC-3′ to give sticky ends. A source. ✓
- (D) Bacillus amyloliquefaciens → BamHI. A source. ✓
- (C) Agrobacterium tumefaciens → this soil bacterium is the "natural genetic engineer of plants": its Ti (tumour-inducing) plasmid is disarmed and used as a cloning vector to deliver genes into plant cells. It lends its name to no restriction enzyme. ✗
Step 3 — Commit.
The question asks for the bacterium that is not a source of a restriction endonuclease, so the odd one out is Agrobacterium tumefaciens.
✓Final answerThe correct option is (C) — Agrobacterium tumefaciens.
ANSWER: C
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