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Q.a) Lucas reagent is an important reagent which helps to distinguish between three classes of alcohols: Write the chemical composition of the Lucas reagent and explain how the above reagent helps to distinguish 1∘1^\circ and 3∘3^\circ-alcohols?

(3)
b) Illustrate preparation of ether by Williamson synthesis with a general chemical equation. (2)
Karnataka PUCKarnataka II PUC Board 2025Subjective· 5mImportance★★★★★
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Lucas reagent (conc. HCl + anhydrous ZnCl₂) distinguishes alcohols by how fast an insoluble chloride (turbidity) forms — instant for 3∘3^\circ, none at room temperature for 1∘1^\circ; Williamson synthesis makes ethers from a sodium alkoxide and an alkyl halide.

(a) Lucas test (3 marks)

Composition of Lucas reagent: concentrated hydrochloric acid mixed with anhydrous zinc chloride (conc. HCl+anhydrous ZnCl2\text{conc. HCl} + \text{anhydrous }\text{ZnCl}_2).

Alcohols react with the reagent to give the corresponding alkyl chloride, which is insoluble in the mixture and appears as turbidity/cloudiness. The reaction goes through a carbocation (SN1\text{S}_\text{N}1), so the rate follows carbocation stability 3∘>2∘>1∘3^\circ > 2^\circ > 1^\circ.

R-OH+HCl→anhy. ZnCl2R-Cl+H2O\text{R-OH} + \text{HCl} \xrightarrow{\text{anhy. ZnCl}_2} \text{R-Cl} + \text{H}_2\text{O}

Distinguishing 1∘1^\circ from 3∘3^\circ:

  • Tertiary (3∘3^\circ) alcohol: forms a very stable 3∘3^\circ carbocation, so turbidity appears immediately at room temperature.
  • Primary (1∘1^\circ) alcohol: forms an unstable 1∘1^\circ carbocation, so there is no turbidity at room temperature; it reacts only on heating.

(A secondary alcohol gives turbidity within about 5 minutes — intermediate behaviour.)

(b) Williamson ether synthesis (2 marks)

An ether is prepared by heating a sodium alkoxide (or phenoxide) with an alkyl halide; the alkoxide oxygen acts as a nucleophile and displaces the halide in an SN2\text{S}_\text{N}2 reaction. …

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