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Q.a) Give a reason for each of the following :

i) The spin only magnetic moment of Sc3+\text{Sc}^{3+} is zero.
(1)
ii) Alloys are readily formed by transition metals.
(1)
b) Write the structure of manganate ion (MnO42−)(\text{MnO}_4^{2-}). (1)
Karnataka PUCKarnataka II PUC Board 2024Subjective· 3mImportance★★★★★
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Figure — Part (b) asks to write the structure of the manganate ion MnO4^2-, which is exactly the canonical tetrahedral
Figure — Part (b) asks to write the structure of the manganate ion MnO4^2-, which is exactly the canonical tetrahedral

Sc3+\text{Sc}^{3+} is d0d^0 so μ=0\mu=0; transition metals form alloys because of similar atomic sizes; MnO42−\text{MnO}_4^{2-} is tetrahedral.

(a)(i) Spin-only magnetic moment of Sc3+\text{Sc}^{3+} is zero.

Scandium (Z = 21) is [Ar]3d14s2[\text{Ar}]3d^1 4s^2. On forming Sc3+\text{Sc}^{3+} it loses the two 4s4s and one 3d3d electron, giving [Ar]3d0[\text{Ar}]3d^0. With no unpaired electrons (n=0n = 0),

μ=n(n+2)=0=0 BM\mu = \sqrt{n(n+2)} = \sqrt{0} = 0\ \text{BM}

(a)(ii) Alloys are readily formed by transition metals.

Transition metals have nearly the same atomic radii (small, comparable sizes across a series). Hence the atoms of one transition metal can easily replace the atoms of another in the metallic crystal lattice, producing solid-solution alloys.

(b) Structure of the manganate ion MnO42−\text{MnO}_4^{2-}. …

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