Skip to content
Question of 182

Q.Express the matrix A=[15−12]A = \begin{bmatrix} 1 & 5 \\ -1 & 2 \end{bmatrix} as the sum of a symmetric and a skew symmetric matrix.

Karnataka PUCKarnataka II PUC Board 2022Subjective· 3mImportance★★★★★
0% · 0/182 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Write A=12(A+A′)+12(A−A′)A = \frac{1}{2}(A+A') + \frac{1}{2}(A-A'); the first part is symmetric and the second skew-symmetric.

Given A=[15−12]A = \begin{bmatrix} 1 & 5 \\ -1 & 2 \end{bmatrix}, so its transpose is A′=[1−152]A' = \begin{bmatrix} 1 & -1 \\ 5 & 2 \end{bmatrix}.

Symmetric part P=12(A+A′)P = \dfrac{1}{2}(A + A'):

A+A′=[2444],P=12[2444]=[1222].A + A' = \begin{bmatrix} 2 & 4 \\ 4 & 4 \end{bmatrix}, \qquad P = \frac{1}{2}\begin{bmatrix} 2 & 4 \\ 4 & 4 \end{bmatrix} = \begin{bmatrix} 1 & 2 \\ 2 & 2 \end{bmatrix}.

Here P′=PP' = P, so PP is symmetric.

Skew-symmetric part Q=12(A−A′)Q = \dfrac{1}{2}(A - A'): …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.