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Q.Express A=[1567]A = \begin{bmatrix} 1 & 5 \\ 6 & 7 \end{bmatrix} as the sum of a symmetric and a skew symmetric matrix.

Karnataka PUCKarnataka II PUC Board 2024Subjective· 3mImportance★★★★★
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Any square matrix splits as A=12(A+A′)+12(A−A′)A=\tfrac12(A+A')+\tfrac12(A-A'), a symmetric plus a skew-symmetric part.

Concept. For any square matrix AA, P=12(A+A′)P=\tfrac12(A+A') is symmetric (P′=PP'=P) and Q=12(A−A′)Q=\tfrac12(A-A') is skew-symmetric (Q′=−QQ'=-Q), with A=P+QA=P+Q.

Given A=[1567]A=\begin{bmatrix}1&5\\6&7\end{bmatrix}, its transpose is A′=[1657]A'=\begin{bmatrix}1&6\\5&7\end{bmatrix}.

Symmetric part:

P=12(A+A′)=12[2111114]=[11121127].P=\frac12(A+A')=\frac12\begin{bmatrix}2&11\\11&14\end{bmatrix}=\begin{bmatrix}1&\tfrac{11}{2}\\[4pt]\tfrac{11}{2}&7\end{bmatrix}.

Skew-symmetric part: …

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