Skip to content
Question of 50

Q.Write the nuclear reaction equation for alpha decay of (238/92)U.

Karnataka PUCKarnataka II PUC Board 2020Subjective· 1mImportance★★★★★
0% · 0/50 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Alpha decay removes 24He^{4}_{2}\text{He}: AA decreases by 4, ZZ by 2, so 92238U→90234Th+24He^{238}_{92}\text{U}\to{}^{234}_{90}\text{Th}+{}^{4}_{2}\text{He}.

Concept. In α\alpha-decay a nucleus emits an alpha particle, which is a helium nucleus 24He^{4}_{2}\text{He}. Both the mass number AA and the atomic number ZZ must be conserved on the two sides of the equation.

Balancing.

  • Mass number: 238=234+4.238 = 234 + 4. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.