Worked Examples · Example 12
Q.Calculate the standard deviation of the values 5, 10, 25, 30 and 50 by the step-deviation method, taking deviations from the arbitrary value 25 and dividing them by the common factor 5.
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Step 1 — Deviations from the arbitrary value 25, then divided by the common factor 5.
| X | d = X − 25 | d′ = d ÷ 5 | d′² |
|---|---|---|---|
| 5 | −20 | −4 | 16 |
| 10 | −15 | −3 | 9 |
| 25 | 0 | 0 | 0 |
| 30 | +5 | +1 | 1 |
| 50 | +25 | +5 | 25 |
| Total | −1 | 51 |
Step 2 — Standard deviation. …
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