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Problems · Example 9.12

Q.Write IUPAC names of the products obtained by addition reactions of HBr to hex-1-ene

(i) in the absence of peroxide and
(ii) in the presence of peroxide.
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The addition of HBr to hex-1-ene follows Markovnikov’s rule in the absence of peroxide (giving 2-bromohexane) and anti-Markovnikov addition in the presence of peroxide (giving 1-bromohexane). The peroxide effect reverses the regioselectivity due to a free-radical mechanism.


Why This Happens: The Concept of Chain Isomerism in Addition Reactions

When HBr adds to an unsymmetrical alkene like hex-1-ene, two possible products can form — chain isomers (same molecular formula, different carbon skeleton arrangement of the bromine atom). The actual product depends entirely on the reaction conditions.

The key is the mechanism:

  • Without peroxide: Ionic mechanism, following Markovnikov’s rule — the hydrogen attaches to the carbon with more hydrogens already.
  • With peroxide: Free-radical mechanism, giving anti-Markovnikov addition — the bromine ends up on the less substituted carbon.

Hex-1-ene is CHX3CHX2CHX2CHX2CH=CHX2\ce{CH3CH2CH2CH2CH=CH2}. Let’s name both products systematically.


Step-by-Step Solution

1. Identify the alkene structure

Hex-1-ene has the double bond between C1 and C2:

CHX3−CHX2−CHX2−CHX2−CH=CHX2\ce{CH3-CH2-CH2-CH2-CH=CH2}

Numbering from the double bond end: C1 (terminal) and C2 (internal).

2. Addition in the absence of peroxide (ionic mechanism)

HBr ionises to HX+\ce{H+} and BrX−\ce{Br-}. The proton attacks the double bond, forming the more stable carbocation. The secondary carbocation at C2 is more stable than the primary at C1. So HX+\ce{H+} adds to C1, giving a carbocation at C2. Then BrX−\ce{Br-} attacks C2.

Product: bromine at C2, hydrogen at C1.

IUPAC name: 2-bromohexane.

3. Addition in the presence of peroxide (free-radical mechanism) …

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