Q.Would you expect the hydrides of N, O and F to have lower boiling points than the hydrides of their subsequent group members ? Give reasons.
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Hydrogen Bonding: From Intuition to Precision
Imagine you're holding two magnets. If you bring the north pole of one close to the south pole of another, they snap together. Now imagine a much weaker version of that — a tiny tug, not a full lock. That's the spirit of hydrogen bonding.
In chemistry, atoms in a molecule share electrons through covalent bonds. But electrons aren't shared equally in all cases. Some atoms are greedy — they pull the shared electrons closer to themselves. Oxygen, nitrogen, and fluorine are the biggest electron-hoarders. When one of these atoms bonds with hydrogen, the hydrogen ends up with a slight positive charge (because its electron has been pulled away), and the other atom gets a slight negative charge.
Now here's the key: that slightly positive hydrogen is attracted to any nearby slightly negative atom (like oxygen, nitrogen, or fluorine) on another molecule. This attraction is a hydrogen bond.
A hydrogen bond is not a true chemical bond like a covalent or ionic bond. It's an intermolecular force — a strong dipole-dipole attraction — but weaker than covalent bonds (about 1/10th to 1/20th the strength).
The Precise Definition
A hydrogen bond is an attractive interaction between a hydrogen atom covalently bonded to a highly electronegative atom (N, O, or F) and another electronegative atom (N, O, or F) that has a lone pair of electrons.
We can write it as:
X—H⋯Y
where X and Y are N, O, or F. The dotted line (⋯) represents the hydrogen bond. X—H is the donor (the molecule that provides the hydrogen), and Y is the acceptor (the molecule that provides the lone pair).
Why Only N, O, and F?
Three things make these three elements special:
- High electronegativity — They pull electrons hard, creating a large partial positive charge on hydrogen.
- Small size — The lone pair on Y is compact, allowing the hydrogen to get very close. Closer distance means stronger attraction.
- Lone pairs — They have unshared electron pairs that can act as the acceptor.
Chlorine is electronegative, but it's too large — the hydrogen can't get close enough for a strong bond. Carbon is not electronegative enough.
What Makes Hydrogen Bonding Special?
Unlike other dipole-dipole interactions, hydrogen bonds are directional and stronger. They're about 5–30 kJ/mol, compared to 0.5–2 kJ/mol for ordinary van der Waals forces. This strength has dramatic consequences.
Real-World Consequences
Water's high boiling point — Water (H2O) boils at 100∘C, while hydrogen sulfide (H2S) boils at −60∘C. Both are similar molecules, but water forms hydrogen bonds; H2S does not (sulfur is not electronegative enough). Those bonds must be broken to boil water, requiring much more energy.
Ice floats — In liquid water, molecules jostle and form temporary hydrogen bonds. When water freezes, the molecules arrange into a hexagonal lattice held open by hydrogen bonds. This structure is less dense than liquid water — hence ice floats. Without hydrogen bonding, ice would sink, and lakes would freeze from the bottom up, killing aquatic life.
DNA double helix — The two strands of DNA are held together by hydrogen bonds between base pairs (adenine-thymine and guanine-cytosine). These bonds are strong enough to keep the strands together, but weak enough to be unzipped during replication. …
Why this formula?
Hydrogen Bonding: Why It Happens — The Reasoning, Not Just the Rule
Hydrogen bonding is not a full covalent bond — it's a special type of intermolecular attraction. To understand why it occurs, we must look at the electronic structure of the atoms involved.
1. The Core Requirement: A "Naked" Proton
A hydrogen bond forms when a hydrogen atom is covalently bonded to a highly electronegative atom (like F, O, or N). Why?
- Electronegativity difference pulls the bonding electron pair strongly toward the electronegative atom.
- The hydrogen atom is left with almost no electron cloud — it becomes a partially positive proton (δ+).
Key idea: The hydrogen is now a small, dense positive charge — it can get very close to a lone pair on another electronegative atom.
2. The Electrostatic Attraction (The "Why")
The partially positive hydrogen (δ+) is attracted to a lone pair of electrons on another electronegative atom (the acceptor).
This is electrostatic — Coulomb's law governs it:
F=4πε01⋅r2q1q2
- q1 = partial positive charge on H
- q2 = partial negative charge on lone pair
- r = distance between them
Because the hydrogen is so small, r is very small → force is strong (stronger than van der Waals, weaker than covalent).
3. Why Only F, O, N?
Not all electronegative atoms work. The atom must have:
| Property | Why it matters |
|---|---|
| High electronegativity | Pulls electron density away from H, creating δ+ |
| Small atomic size | Allows close approach of the H to the lone pair |
| At least one lone pair | Provides the negative site for attraction |
F, O, and N satisfy all three. Cl is electronegative but too large — the H cannot get close enough for a strong bond.
4. The "Formula" for Hydrogen Bond Strength
There is no single formula for hydrogen bond energy, but the strength depends on:
EH-bond∝r2δ+⋅δ−
Where:
- δ+ = partial charge on H (depends on electronegativity of donor atom)
- δ− = partial charge on acceptor lone pair
- r = distance between H and acceptor atom
Typical strengths (for context):
- Covalent bond: ~400 kJ/mol
- Hydrogen bond: 10–40 kJ/mol
- van der Waals: ~1–5 kJ/mol
5. Directionality — The "Linear" Preference
Hydrogen bonds are directional: the strongest interaction occurs when the donor H–X bond and the acceptor lone pair are collinear (180° angle).
Why? Because:
- The positive charge on H is concentrated along the bond axis …
No — NH3, H2O and HF have unexpectedly higher boiling points than the hydrides of the elements below them in their groups, because of strong intermolecular hydrogen bonding. …
N, O and F are the smallest, most electronegative elements of their respective groups (15, 16, 17). Their hydrides (NH3, H2O, HF) have highly polar N–H, O–H and F–H bonds, and each of these atoms carries lone pair(s) of electrons.
This combination — a very electronegative atom, a small size, and available lone pairs — allows strong intermolecular hydrogen bonding between one molecule's H (attached to N/O/F) and the lone pair on N/O/F of a neighbouring molecule. …
Compare the electronegativity and lone-pair availability of N, O, F versus their group successors; identify hydrogen bonding as the reason for the anomaly, …
- Answering "yes" by reading the question literally without checking the actual chemistry (hydrogen bonding raises, not lowers, boiling point). …
- KEAM 2026Set eng-2026-04224 marksMCQQ.The compound which has the highest freezing point (in K) is (A) CS2 (B) CHCl3 (C) (C2H5)2O (D) H2O (E) C2H5OH
›Reveal solutionSolution
H2O has the highest freezing point (273 K); CS2, CHCl3, diethyl ether and ethanol all freeze at much lower temperatures. …
- KEAM 2025Set eng-2025-04264 marksMCQQ.In which of the following liquid inter molecular hydrogen bonding does not exist? (A) CH3COOH (B) C2H5OH (C) Phenol (D) Diethylether (E) Ethylamine
›Reveal solutionSolution
Hydrogen bonding needs H attached to a highly electronegative atom (O/N/F); diethyl ether lacks such an H.
Intermolecular hydrogen bonding requires a hydrogen atom covalently bonded to a strongly electronegative atom (O, N, F).
- CH3COOH, C2H5OH, phenol have O–H; ethylamine has N–H — all can hydrogen bond. …
- KEAM 2024Set eng-2024-06054 marksMCQQ.Which of the following explains why dimethyl ether has lower boiling point than its isomeric compound, ethanol? (A) Resonance (B) London dispersion forces (C) Hybridisation (D) Van der Waals forces (E) Hydrogen bonding
›Reveal solutionSolution
Ethanol's O–H allows hydrogen bonding between molecules; dimethyl ether (no O–H) cannot H-bond, so it boils lower.
Both C2H6O isomers have similar molar mass and dispersion forces. The decisive difference is that ethanol (CH3CH2OH) engages in strong intermolecular hydrogen bonding through its –OH group, requiring more energy to vaporise. Dim …
- KEAM 2024Set eng-2024-06064 marksMCQQ.Strong intra-molecular hydrogen bond is present in (A) water (B) hydrogen fluoride (C) o-cresol (D) o-nitrophenol (E) ammonia
›Reveal solutionSolution
o-nitrophenol forms an intramolecular H-bond between its −OH and the adjacent −NO2 group.
In o-nitrophenol the hydroxyl hydrogen and the oxygen of the ortho nitro group are close enough to form a six-membered chelate ring through hydrogen bonding within the same molecule (intramolecular). Water, HF and ammo …
- KEAM 2023Set eng-2023-P1-A14 marksMCQQ.HF is a liquid unlike other hydrogen halides because : (A) H-F bond is strong (B) Hydrogen bonding is present (C) HF is a weak acid (D) F atom is smaller in size (E) HF is a strong base
›Reveal solutionSolution
HF is a liquid unlike other hydrogen halides because of extensive intermolecular hydrogen bonding.
Concept and Intuition
Fluorine is highly electronegative and small, so H-F molecules associate through strong hydrogen bonds forming chains. These raise the boiling point enough that HF is a liquid, while HCl, HBr, HI are gases at room temperature.
Step-by-Step Solution
- HCl, HBr, HI have only weak dipole/dispersion forces → gases.
- In HF, strong F...H-F hydrogen bonding links molecules. …
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