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Exercises · 5.3

Q.Using the equation of state pV=nRT; show that at a given temperature density of a gas is proportional to gas pressure p.

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Step 1 – Start from the ideal gas equation

pV=nRTpV = nRT

Step 2 – Express moles in terms of mass

For a gas of mass mm and molar mass MM:

n=mMn = \frac{m}{M}

Substituting:

pV=mMRTpV = \frac{m}{M}RT

Step 3 – Isolate density (d=m/Vd = m/V)

Rearranging:

p=mV⋅RTMp = \frac{m}{V}\cdot\frac{RT}{M}

Since d=m/Vd = m/V:

p=dRTMp = \frac{dRT}{M}

  ⟹  d=pMRT\implies \quad d = \frac{pM}{RT}

Step 4 – Interpret at constant temperature

At a GIVEN (fixed) temperature TT, for a specified gas, both MM (molar mass) and RR (universal gas constant) are constants. Therefore:

d=(MRT)p=(constant)×pd = \left(\frac{M}{RT}\right)p = (\text{constant}) \times p

  ⟹  d∝pat constant T\implies \boxed{d \propto p} \quad \text{at constant } T

This confirms that density is directly proportional to pressure at a fixed temperature — doubling the pressure (compressing the gas into less space at the same TT) doubles its density.

✓Final answer

d=pMRTd = \dfrac{pM}{RT}, so at constant TT: d∝p\boxed{d \propto p}

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