Q.Account for the following :
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Start your 14-day free trial to unlock the full solution →(a) Solvated (ammoniated) electrons give the blue colour. (b) Li-Mg diagonal relationship (similar charge/size ratio). (c) Na2CO3 hydrolyses to give OH- -> alkaline. (d) High hydration enthalpy of small Be2+/Mg2+ makes their sulphates soluble.
(a) When an alkali metal dissolves in liquid ammonia it ionises to give the metal cation and an electron; both are solvated (ammoniated): M + (x+y)NH3 -> M+(NH3)x + e-(NH3)y. The ammoniated (free) electrons absorb light in the visible region, so dilute solutions look deep blue and are paramagnetic and good conductors.
(b) Lithium and magnesium exhibit a diagonal relationship: Li (period 2, group 1) and Mg (period 3, group 2) have nearly equal charge-to-size ratios (polarising power). Consequently both react with N2 to form nitrides (Li3N, Mg3N2), both give only normal oxides on burning, both form covalent, water-soluble chlorides that are deliquescent, and their carbonates decompose on heating.
(c) Sodium carbonate is a salt of a strong base (NaOH) and a weak acid (carbonic acid). In water the carbonate ion undergoes hydrolysis:
CO3^2- + H2O <=> HCO3- + OH-.
The OH- ions produced make the solution basic (alkaline).
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