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Worked Examples · Example 9
Q.

Find the variance and standard deviation for the following data:

xix_ifif_i
43
85
119
175
204
243
321
Kerala DhseTextbookSubjective· 5mImportance★★★★★est
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The mean is 1414; the variance is 45.845.8 and the standard deviation is 45.8≈6.77\sqrt{45.8} \approx 6.77.

Understanding Variance and Standard Deviation

Variance is the frequency-weighted average of the squared deviations from the mean; the standard deviation is its square root, returning the measure to the original units.

σ2=∑fi(xi−xˉ)2N,σ=σ2\sigma^2 = \frac{\sum f_i (x_i - \bar{x})^2}{N}, \qquad \sigma = \sqrt{\sigma^2}

Step-by-Step Solution

1. Total frequency and mean

N=3+5+9+5+4+3+1=30N = 3+5+9+5+4+3+1 = 30

∑fixi=12+40+99+85+80+72+32=420,xˉ=42030=14\sum f_i x_i = 12+40+99+85+80+72+32 = 420, \qquad \bar{x} = \frac{420}{30} = 14

2. Squared deviations weighted by frequency

xix_ifif_ixi−14x_i-14(xi−14)2(x_i-14)^2fi(xi−14)2f_i(x_i-14)^2
43−10-10100300
85−6-636180
119−3-3981
17533945
2046636144
2431010100300
3211818324324

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