Q.Equation of the line passing through (1,2) and parallel to the line y=3x−1 is
(A) y+2=x+1
(B) y+2=3(x+1)
(C) y−2=3(x−1)
(D) y−2=x−1
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Slope Calculation
Slope Calculation — From Intuition to Precision
Imagine you're walking up a hill. Some hills are gentle — you barely notice the climb. Others are so steep you have to lean forward and use your hands. That "steepness" is what slope measures. In mathematics, slope tells us how fast a line rises or falls as we move from left to right.
The Intuition: Rise Over Run
Take any two points on a straight line. As you walk from the left point to the right point, two things happen:
- You move horizontally — that's the run.
- You move vertically — that's the rise (upwards) or fall (downwards).
Slope is simply the ratio:
Slope = (vertical change) ÷ (horizontal change)
If you climb 3 metres while walking 5 metres forward, the slope is 3/5=0.6. If you descend 2 metres while walking 4 metres forward, the slope is −2/4=−0.5 — negative because you're going downhill.
The Precise Definition
Given two distinct points (x1,y1) and (x2,y2) on a non-vertical line, the slope m is:
m=x2−x1y2−y1
The numerator is the rise (change in y), the denominator is the run (change in x). The order matters: subtract the first point's coordinates from the second's, consistently.
Never divide by zero. If x2=x1, the line is vertical — slope is undefined (not zero, not infinite — just undefined).
What the Number Tells You
| Slope value | What the line does |
|---|---|
| m>0 | Rises left to right (uphill) |
| m<0 | Falls left to right (downhill) |
| m=0 | Horizontal (flat) |
| m undefined | Vertical (straight up/down) |
The larger the absolute value ∣m∣, the steeper the line. A slope of 5 is much steeper than a slope of 0.2.
A Worked Example
Find the slope of the line through (1,2) and (4,8).
Step 1: Label the points. Let (x1,y1)=(1,2) and (x2,y2)=(4,8).
Step 2: Compute the rise: y2−y1=8−2=6.
Step 3: Compute the run: x2−x1=4−1=3.
Step 4: Divide: m=36=2.
The line rises 2 units vertically for every 1 unit it moves right. …
Parallel lines share the same slope. y=3x−1 has slope m=3.
Using point-slope form through (1,2) with m=3:
y−2=3(x−1) …
Parallel lines share the same slope. The given line has slope 3, so using point-slope form with (1,2) and m=3 gives y−2=3(x−1) — option (C).
Step 1: Slope of the given line
y=3x−1 is already in slope-intercept form y=mx+c, so its slope is m=3.
Step 2: Line through (1,2) with the same slope
Parallel lines never meet, which algebraically means they share the same slope. Using the point-slope form y−y1=m(x−x1) with (x1,y1)=(1,2) and m=3:
y−2=3(x−1)
This matches option (C) directly. …
- KEAM 2026Set eng-2026-04184 marksMCQQ.Let O be the origin and let P be a point on the line x+3y=10. If OP is perpendicular to the line, then the angle between OP and the y-axis is (A) 15∘ (B) 30∘ (C) 45∘ (D) 60∘ (E) 75∘
›Reveal solutionSolution
The foot of perpendicular lies along the line's normal (1,3), which makes 30∘ with the y-axis.
The line x+3y=10 has normal direction (1,3). Since OP⊥ line, OP points along this normal.
The angle α between OP and the y-axis (unit (0,1)) satisfies …
- KEAM 2026Set eng-2026-04194 marksMCQQ.A straight line makes y-intercept of 5. If the angle made by the line with y-axis is 60o and the line intersects x-axis in the negative direction, then the equation of the line is (A) x+3y+53=0 (B) x−3y+53=0 (C) 3x−y+5=0 (D) 3x+y+5=0 (E) 3x−y+53=0
›Reveal solutionSolution
The line makes 30∘ with the x-axis (slope 1/3), passes through (0,5), and cuts the negative x-axis.
Angle with y-axis =60∘⇒ angle with x-axis =30∘, so slope m=tan30∘=31.
Line through (0,5): y=31x+5⇒3y=x+53⇒x−3y+53=0. …
- KEAM 2026Set eng-2026-04194 marksMCQQ.The perpendicular drawn from the origin to the straight line 3x+y−24=0 makes an angle α with the positive direction of x-axis. Then α is equal to (A) 120o (B) 45o (C) 135o (D) 60o (E) 30o
›Reveal solutionSolution
The foot-of-perpendicular direction is the line's normal (3,1), giving cosα=23, sinα=21. …
- KEAM 2026Set eng-2026-04204 marksMCQQ.A straight line has y-intercept −5. If it makes 120∘ with the x-axis, then the equation of the line is (A) 3x+y+20=0 (B) 3x+y+10=0 (C) 3x−y+10=0 (D) 3x+y−10=0 (E) 3x+y+5=0
›Reveal solutionSolution
The line makes 120∘ with the x-axis, so slope m=tan120∘=−3. With y-intercept −5, its equation y=−3x−5 rearranges to 3x+y+5=0.
The angle of inclination is 120∘, so
m=tan120∘=−3. …
- KEAM 2025Set eng-2025-04284 marksMCQQ.If the line joining of two points (1,0) and (4,3) is rotated about the point (1,0) in counter clockwise direction through an angle 15∘, then the equation of the line in the new position is (A) 3x−2y−3=0 (B) 3x−y−3=0 (C) x+y−1=0 (D) x+3y−1=0 (E) 3x−y−3=0
›Reveal solutionSolution
The line inclined at 45∘ becomes inclined at 60∘ after a 15∘ rotation; its equation through (1,0) is 3x−y−3=0.
The line joining (1,0) and (4,3) has slope
m=4−13−0=1,
so it makes an angle of 45∘ with the x-axis. …
- KEAM 2025Set eng-2025-04284 marksMCQQ.If the normal form of the equation of a straight line x+3y=23 is xcosα+ysinα=p then the values of α and p are respectively (A) 6π and 6 (B) 3π and 6 (C) 3π and 3 (D) 6π and 3 (E) 4π and 6
›Reveal solutionSolution
Normalize by the coefficient magnitude 2; the cosine/sine give α=3π and p=3.
The equation is x+3y=23. The magnitude of the coefficient vector is 12+(3)2=2.
Dividing throughout by 2:
21x+23y=3. …
- KEAM 2025Set eng-2025-04294 marksMCQQ.If a straight line passes through the points (2−1,1) and (1,2), then its y-intercept is (A) 4 (B) 3 (C) −4 (D) 3−4 (E) 34
›Reveal solutionSolution
Slope through (−21,1) and (1,2) is 1+1/22−1=32; setting x=0 in y−2=32(x−1) gives y=34. …
- KEAM 2023Set eng-2023-P2-B24 marksMCQQ.A thin particle moves from (0,1) and gets reflected upon hitting the x-axis at (3,0). Then the slope of the reflected line is (A) 31 (B) −31 (C) 3 (D) −3 (E) 0
›Reveal solutionSolution
The reflected ray has slope 31.
Concept and Intuition
Reflection in the x-axis reverses the sign of the slope of the incident ray.
Step-by-Step Solution
- Incident ray from (0,1) to (3,0) has slope 3−00−1=−31.
- On reflection about the x-axis the slope changes sign. …
- KEAM 2021Set eng-2021-P2-B14 marksMCQQ.A straight line makes an angle α with the positive direction of x-axis, where cosα=23. If it passes through (0,−2), then its equation is (A) 3x+y+2=0 (B) 3y+x+2=0 (C) 3y+x+23=0 (D) 3y−x+23=0 (E) 3x+y−23=0
›Reveal solutionSolution
The line is 3y−x+23=0.
Concept and Intuition
The slope is tanα; with cosα=23, α=30∘ and tanα=31. Use the y-intercept −2.
Step-by-Step Solution
- Slope =tan30∘=31.
- y=31x−2. …
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