Q.For a point on a rotating rigid body, the graph of its angular position θ (plotted on the vertical axis) against time t (plotted on the horizontal axis) is a straight line of constant positive slope: θ increases uniformly with t, passing steadily through successive instants t1<t2<t3. Is the body rotating clockwise or anti-clockwise? Give the reason.
Imagine you're watching a ceiling fan. You know it's moving, but how do you describe how fast it's spinning? You could say "it makes 3 full turns every second" — that's a measure of angular velocity. But let's build this idea from the ground up.
The Intuition: Speed vs. Turning Speed
When a car moves in a straight line, we talk about its linear velocity — how many meters it covers per second. But when something rotates — a wheel, a planet, a spinning top — every point on it moves in a circle. The outer edge of a wheel travels a much longer distance in one rotation than a point near the centre. So if we tried to use ordinary speed (metres per second), we'd get different numbers for different parts of the same object. That's messy.
What we need is a quantity that describes the rotation itself, independent of how far a point is from the centre. That quantity is angular velocity.
The Core Idea
Angular velocity tells you how fast the angle is changing as something rotates. Instead of "metres per second," it's "radians per second" (or degrees per second, or revolutions per second).
Note
A radian is the natural unit for angles in physics. One full circle = 2π radians ≈ 6.28 rad. So "1 radian per second" means the object sweeps out an angle of about 57.3° every second.
The Precise Definition
Let an object rotate about a fixed axis. At time t, let its angular position be θ(t) — the angle it has turned through from some reference line. Then:
ω=dtdθ
where ω (Greek letter omega) is the instantaneous angular velocity. For uniform rotation (constant speed), this simplifies to:
ω=ΔtΔθ
Units: radians per second (rad/s). In practice, you'll also see revolutions per minute (rpm) — 1 rpm = 602π rad/s.
Direction Matters: Angular Velocity as a Vector
Here's where it gets interesting. Angular velocity isn't just a number — it has a direction. But the direction isn't "clockwise" or "anticlockwise" in the plane of rotation. Instead, it points along the axis of rotation, following the right-hand rule:
Tip
Curl the fingers of your right hand in the direction of rotation. Your thumb points in the direction of the angular velocity vector ω.
So a spinning wheel's angular velocity vector points straight out from its axle. If the wheel spins faster, the vector gets longer. If it reverses direction, the vector flips.
Connecting to Linear Velocity
Here's the payoff: once you know the angular velocity of a rotating object, you can find the linear speed of any point on it. For a point at distance r from the axis:
v=ωr
This is why the outer edge of a merry-go-round moves faster than a point near the centre — same ω, different r.
Watch out
This formula v=ωr only works when v is the tangential speed (perpendicular to the radius). It does NOT apply to radial motion (straight in or out).
The straight θ-t line has a constant positive slope, so the angular velocity ω=dθ/dt is positive and constant. Increasing angular position corresponds, by the usual sign convention, to anti-clockwise rotation. …
A straight-line θ versus t graph means θ changes at a constant rate, so the angular velocity ω=dθ/dt is constant. Its slope here is positive, so θ is increasing. By the standard convention that increasing angular position is measured anti-clockwise, the body turns anti-clockwise.
Concept
Angular velocity is the slope of the angular-position–time graph: ω=dtdθ.
Reasoning
The graph is a straight line, so dtdθ is constant — the rotation is uniform.
The slope is positive, so ω>0; the angular position θ keeps increasing with time. …
Same / Similar Concept — real previous-year questions on the same or a closely similar concept, not this exact question.
KEAM 2026Set eng-2026-04214 marksMCQ
Q.If the angular speed of a particle moving in a circular path of radius 1.2 m is increased from 2rads−1 to 4rads−1 keeping its radius constant, then its linear speed is increased by
(A) 1.6ms−1
(B) 2.4ms−1
(C) 3.6ms−1
(D) 4.8ms−1
(E) 6ms−1
›Reveal solutionSolution
Linear speed v=rω; with r constant, Δv=rΔω=1.2×2=2.4ms−1.
Q.The ratio of angular speeds of the minute hand and second hand of a watch is
(A) 1:12
(B) 1:6
(C) 1:60
(D) 12:1
(E) 60:1
›Reveal solutionSolution
The minute hand and second hand have angular speeds in the ratio 1:60.
Concept and Intuition
Angular speed is inversely proportional to the time period of rotation, ω=2π/T. The minute hand completes one full turn in 60 minutes (3600 s), while the second hand completes one turn in 60 s.
Q.If the angular displacement made by a rotating wheel in 10 s is 150π radian, then the number of revolutions made by it is
(A) 75
(B) 100
(C) 300
(D) 150
(E) 50
›Reveal solutionSolution
One revolution equals 2π radians, so dividing the total angular displacement by 2π gives 75 revolutions.
Q.The CORRECT statement for a rigid body rotating about a fixed axis with angular velocity ω is
(A) ω is directed perpendicular to the axis of rotation
(B) all the particles move with same speed
(C) ω is a scalar quantity
(D) ω has no direction
(E) different particles move in different circles
›Reveal solutionSolution
Each particle moves in a circle whose plane is perpendicular to the axis and whose radius is its distance from the axis; particles at different radii move in different circles with different linear speeds (v=ωr). …
Q.For a smoothly running analog clock, the ratio of the angular velocity of the minute hand to the angular velocity of hour hand is
(A) 2
(B) 12
(C) 24
(D) 60
(E) 360
›Reveal solutionSolution
Angular velocity ω=2π/T, so the ratio is inverse to the periods.
The minute hand completes a revolution in 60 min; the hour hand in 12×60=720 min. …