Q.(a) A string is stretched between two fixed supports and a note of sound is heard when it is plucked at its middle point.
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Start your 14-day free trial to unlock the full solution →A plucked string reflects its wave at both fixed ends; the incident and reflected waves superpose to give a standing wave with fixed nodes at the ends. Only wavelengths λₙ = 2L/n fit this condition, giving discrete frequencies νₙ = nv/2L. The fundamental (n=1) and first overtone (n=2) are ν₁ = v/2L and ν₂ = v/L. Sound is loudest at an antinode.
(a)(i) How standing waves are produced
When the string is plucked, a transverse wave travels along it in both directions. At each fixed support the wave is reflected (with a phase reversal, since the support cannot move). The forward-travelling wave and its reflection are two waves of the same amplitude and frequency moving in opposite directions on the same string. By the principle of superposition they combine to form a standing (stationary) wave — a wave pattern that does not travel, with fixed points of zero displacement (nodes) and fixed points of maximum displacement (antinodes).
Because the string is clamped at both ends, the displacement at x = 0 and x = L must always be zero — the ends are forced to be nodes. Only those wave patterns that place a node exactly at both ends can exist as a persistent (resonant) standing wave on the string; all other wavelengths destructively interfere with themselves over time and die out.
(a)(ii) Frequency of the first two modes
Let the string have length L. A standing wave with p complete loops (each loop = half a wavelength, since a loop runs node-to-node) fits the string when
L = n·(λₙ/2), n = 1, 2, 3, …
⟹ λₙ = 2L/n
The wave speed on the string is v = √(T/μ), where T is the tension and μ the mass per unit length. Since v = νλ,
νₙ = v/λₙ = nv/2L
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First mode (fundamental, n = 1): one loop (a single antinode at the centre).
λ₁ = 2L ⟹ ν₁ = v/2L
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Second mode (first overtone, n = 2): two loops, with a node at the midpoint.
λ₂ = L ⟹ ν₂ = v/L = 2ν₁
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