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Exercise 12.3 · Q3

Q.The towers of a suspension bridge, hang in the form of a parabola, have their tops 30 metres above the roadway and are 200 metres apart. If the cable is 5 metres above the roadway at the centre of the bridge, find the length of the vertical supporting cable 30 metres from the centre.

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Model the cable as a parabola with vertex at the lowest point (centre, 5 m above roadway); use the tower data (30 m above roadway, 100 m from centre) to fix the parabola, then find the cable height 30 m from the centre.

Parabola with vertex at origin, axis vertical, opening upward (measuring yy as rise above the vertex): x2=4ayx^2=4ay.

  1. The towers are 200 m apart, so each is at x=100x=100 m from the centre.
  2. Place the origin at the vertex — the lowest point of the cable, which is 5 m above the roadway at the centre. Let yy = rise of the cable above this lowest point.
  3. At the tower, the cable is 30 m above the roadway, so it has risen y=30−5=25y=30-5=25 m above the vertex.
  4. Substitute (100,25)(100,25) into x2=4ayx^2=4ay: 1002=4a(25)⇒10000=100a⇒a=100100^2=4a(25)\Rightarrow10000=100a\Rightarrow a=100.
  5. Parabola: x2=400y⇒y=x2400x^2=400y\Rightarrow y=\dfrac{x^2}{400}. …

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