Q.The towers of a suspension bridge, hang in the form of a parabola, have their tops 30 metres above the roadway and are 200 metres apart. If the cable is 5 metres above the roadway at the centre of the bridge, find the length of the vertical supporting cable 30 metres from the centre.
Angle Between Two Lines – From Intuition to Precision
When you think of two lines crossing each other, the first thing you notice is how "wide" or "narrow" the opening between them is. That opening is the angle between the lines. If you hold two pens and let them cross, the smaller turn you make to bring one pen onto the other is the angle between them.
But here's the key: two intersecting lines actually make four angles — two acute (sharp) and two obtuse (wide), or all four right angles if they are perpendicular. By convention, when we say "the angle between two lines," we always mean the smaller (acute) angle, which lies between 0∘ and 90∘. If the lines are parallel, the angle is 0∘; if they are perpendicular, it is 90∘.
The Geometry of Slopes
Every non-vertical line in the coordinate plane has a slopem, which tells you how steep it is. The slope is the tangent of the angle the line makes with the positive x-axis. So if a line makes an angle θ with the x-axis, then m=tanθ.
Now imagine two lines with slopes m1 and m2. They make angles θ1 and θ2 with the x-axis. The angle between the lines themselves is simply the difference between these two angles: ∣θ1−θ2∣.
tanϕ=1+m1m2m1−m2
Here ϕ is the acute angle between the two lines. The absolute value ensures we get the smaller angle. The denominator 1+m1m2 comes from the tangent subtraction formula: tan(θ1−θ2)=1+tanθ1tanθ2tanθ1−tanθ2.
Why the Formula Works
Suppose line L1 has slope m1=tanθ1 and line L2 has slope m2=tanθ2. The angle between them is ϕ=∣θ1−θ2∣. Using the tangent subtraction identity:
The absolute value guarantees we take the acute angle. If 1+m1m2=0, the denominator is zero, meaning tanϕ is undefined — that happens when ϕ=90∘, i.e., the lines are perpendicular.
Watch out
If 1+m1m2=0, do not use the formula directly. The lines are perpendicular, so ϕ=90∘. The formula simply tells you the angle is 90∘ by giving an undefined tangent.
Special Cases
Parallel lines: m1=m2. Then numerator is zero, so tanϕ=0, giving ϕ=0∘.
Perpendicular lines: m1m2=−1. Then denominator is zero, so ϕ=90∘. …
Modelling the cable as an upward-opening parabola with its vertex at the lowest point (the centre, 5 m above the roadway), the tower data (height and horizontal distance) fixes the parabola, which then gives the cable's height at any distan …
Model the cable as a parabola with vertex at the lowest point (centre, 5 m above roadway); use the tower data (30 m above roadway, 100 m from centre) to fix the parabola, then find the cable height 30 m from the centre.
Parabola with vertex at origin, axis vertical, opening upward (measuring y as rise above the vertex): x2=4ay.
The towers are 200 m apart, so each is at x=100 m from the centre.
Place the origin at the vertex — the lowest point of the cable, which is 5 m above the roadway at the centre. Let y = rise of the cable above this lowest point.
At the tower, the cable is 30 m above the roadway, so it has risen y=30−5=25 m above the vertex.
Substitute (100,25) into x2=4ay: 1002=4a(25)⇒10000=100a⇒a=100.