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Miscellaneous Exercise · Q10

Q.Number of diagonals of a convex hexagon are:

(i) 3
(ii) 6
(iii) 9
(iv) 15
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A hexagon's diagonals are all vertex-pairs except its 6 sides.

Number of diagonals of a convex nn-gon =nC2−n=n(n−3)2= {}^nC_2-n=\dfrac{n(n-3)}{2}, since nC2^nC_2 counts every pair of vertices (sides + diagonals) and the nn sides must be removed.

  1. A hexagon has n=6n=6 vertices. Every line segment joining 2 vertices is either a side or a diagonal, and there are 6C2=6×52×1=15^6C_2=\dfrac{6\times5}{2\times1}=15 such segments in total. …

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