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Worked Examples · Example 7

Q.Let A={1,2,3,4,5,6}A = \{1, 2, 3, 4, 5, 6\}. Define a relation RR from AA to AA by:
R={(x,y):x>y}R = \{(x, y) : x > y\}
  1. Write the given relation in tabular or roster form.
  2. Define this relation using an arrow diagram.
  3. Write the domain, range and co-domain of RR.

Ladakh CbseNCERTSubjective· 3mImportance★★★★★est
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✓ Free question

Listing every pair with x>yx>y from A={1,…,6}A=\{1,\dots,6\} gives 1515 ordered pairs, with Domain {2,3,4,5,6}\{2,3,4,5,6\}, Range {1,2,3,4,5}\{1,2,3,4,5\}, and Co-domain the full set AA.

R={(x,y):x>y, x,y∈A}⊆A×AR=\{(x,y): x>y,\ x,y\in A\}\subseteq A\times A

Domain of RR = set of all xx that actually appear as a first element of some pair in RR. Range of RR = set of all yy that actually appear as a second element. Co-domain = the full target set AA (by definition, regardless of which elements are actually used).

  1. List every pair (x,y)(x,y) with x,y∈A={1,2,3,4,5,6}x,y\in A=\{1,2,3,4,5,6\} and x>yx>y, going through x=2x=2 to x=6x=6:
  • x=2x=2: (2,1)(2,1)
  • x=3x=3: (3,1),(3,2)(3,1),(3,2)
  • x=4x=4: (4,1),(4,2),(4,3)(4,1),(4,2),(4,3)
  • x=5x=5: (5,1),(5,2),(5,3),(5,4)(5,1),(5,2),(5,3),(5,4)
  • x=6x=6: (6,1),(6,2),(6,3),(6,4),(6,5)(6,1),(6,2),(6,3),(6,4),(6,5)

So (roster form):

R={(2,1),(3,1),(3,2),(4,1),(4,2),(4,3),(5,1),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)}R=\{(2,1),(3,1),(3,2),(4,1),(4,2),(4,3),(5,1),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)\}

Total pairs =1+2+3+4+5=15=(62)=1+2+3+4+5=15=\binom{6}{2} (choosing any 2 distinct elements, the larger is always xx).

  1. Arrow diagram (description). Draw set A={1,…,6}A=\{1,\dots,6\} twice, side by side (left copy = domain side, right copy = range side). For every pair (x,y)∈R(x,y)\in R, draw an arrow starting at xx in the left copy and ending at yy in the right copy — e.g. an arrow from 2→12\to1, from 3→13\to1 and 3→23\to2, and so on, giving 1515 arrows in total, with no arrows starting at 11 (since 11 is never >> any other element of AA) and no arrows ending at 66 (since 66 is never << any other element).

  2. Domain — every xx that appears as a first component: {2,3,4,5,6}\{2,3,4,5,6\} (note 11 is excluded, since 11 cannot be >> anything in AA).

  3. Range — every yy that appears as a second component: {1,2,3,4,5}\{1,2,3,4,5\} (note 66 is excluded, since nothing in AA exceeds 66).

  4. Co-domain — by definition of "a relation from AA to AA", the co-domain is the full set A={1,2,3,4,5,6}A=\{1,2,3,4,5,6\}.

Self-check: ∣R∣=15=(62)|R|=15=\binom{6}{2}, consistent with choosing any unordered pair of distinct elements from a 6-element set and always putting the larger first.

✓Final answer

R={(2,1),(3,1),(3,2),(4,1),(4,2),(4,3),(5,1),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)}R=\{(2,1),(3,1),(3,2),(4,1),(4,2),(4,3),(5,1),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)\} (1515 pairs); Domain ={2,3,4,5,6}=\{2,3,4,5,6\}; Range ={1,2,3,4,5}=\{1,2,3,4,5\}; Co-domain ={1,2,3,4,5,6}=\{1,2,3,4,5,6\}.

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