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Exercises · Q18
Q.

Calculate the correlation coefficient between the heights of fathers in inches (X) and their sons (Y).

X6566576768697072
Y6756656872726971

(Ans. r = 0.603)

Ladakh CbseNCERTSubjective· 5mImportance★★★★★est
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With N=8N=8 and the raw-score formula, ∑XY=36118, ∑X=534, ∑Y=540, ∑X2=35788, ∑Y2=36644\sum XY=36118,\ \sum X=534,\ \sum Y=540,\ \sum X^{2}=35788,\ \sum Y^{2}=36644, giving r≈+0.44r\approx +0.44 from the printed data — a moderate positive correlation. The book's key states 0.6030.603; that value needs the third X to be 6767, not the printed 5757 (a likely source misprint).

Concept first

For paired measurements we use Karl Pearson's coefficient in raw-score form:

r=N∑XY−∑X ∑Y[N∑X2−(∑X)2] [N∑Y2−(∑Y)2]r=\frac{N\sum XY-\sum X\,\sum Y}{\sqrt{[N\sum X^{2}-(\sum X)^{2}]\,[N\sum Y^{2}-(\sum Y)^{2}]}}

The working table (N=8N=8)

XXYYXYXYX2X^{2}Y2Y^{2}
6567435542254489
6656369643563136
5765370532494225
6768455644894624
6872489646245184
6972496847615184
7069483049004761
7271511251845041
534540361183578836644

Substituting

N∑XY−∑X∑Y=8(36118)−(534)(540)=288944−288360=584N\sum XY-\sum X\sum Y=8(36118)-(534)(540)=288944-288360=584

N∑X2−(∑X)2=8(35788)−5342=286304−285156=1148N\sum X^{2}-(\sum X)^{2}=8(35788)-534^{2}=286304-285156=1148

N∑Y2−(∑Y)2=8(36644)−5402=293152−291600=1552N\sum Y^{2}-(\sum Y)^{2}=8(36644)-540^{2}=293152-291600=1552

r=5841148×1552=5841781696=5841334.8=0.4375r=\frac{584}{\sqrt{1148\times1552}}=\frac{584}{\sqrt{1781696}}=\frac{584}{1334.8}=0.4375

A note on the answer key …

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