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NCERT Exemplar · Q12

Q.Find the centroid of a triangle, the mid-point of whose sides are D(1,2,−3)D(1,2,-3), E(3,0,1)E(3,0,1) and F(−1,1,−4)F(-1,1,-4).

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The centroid of a triangle equals the centroid of the triangle formed by its midpoints; average the coordinates of DD, EE, and FF to get (1,1,−2)\left(1, 1, -2\right).

Why this works

When you're given the midpoints of a triangle's sides rather than its vertices, you might think you need to first recover the original vertices. But here's the beautiful fact: the centroid of the medial triangle (formed by joining the midpoints) is exactly the same as the centroid of the original triangle.

This happens because the medial triangle is similar to the original triangle and positioned such that both share the same center of mass. The centroid divides each median in the ratio 2:12:1 from vertex to midpoint, and this geometric relationship is preserved under the midpoint transformation.

So we can find the centroid directly from DD, EE, and FF by averaging their coordinates.

Solution

The centroid GG of any triangle with vertices (x1,y1,z1)(x_1, y_1, z_1), (x2,y2,z2)(x_2, y_2, z_2), and (x3,y3,z3)(x_3, y_3, z_3) is given by:

G=(x1+x2+x33,y1+y2+y33,z1+z2+z33)G = \left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}, \frac{z_1 + z_2 + z_3}{3}\right)

Since DD, EE, and FF are the midpoints forming the medial triangle, we apply this formula to their coordinates.

  1. Add the xx-coordinates: …

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